How do you calculate wave speed?

The length of the adult mosquito is typically between 3.0 mm and 6.0 mm. The smallest known mosquitoes are around 2.5 mm, and th

FrozenT [24]

0.74in

Explanation:

Given parameters:

length range of adult mosquito = 3.0 - 6.0mm

Smallest mosquito = 2.5mm

Largest mosquito = 19mm

Average mass range = 3.0 - 5.0mg

Unknown:

Length of largest known mosquito in inches = ?

Solution;

The length is the longest dimension. It is how long a body is.

The problem here is converting from mm to inches;

The length of the longest mosquito which is the largest is 19mm

19mm to inches;

1mm = 0.039inches

19mm = 19mm x $\frac{0.039in}{1mm}$ = 0.74in

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4 0

3 years ago

Type the correct answer in the box. Round your answer to the nearest whole number. The mass of Venus is 4.87 × 1024 kilograms, a

den301095 [7]

The gravitational effect on other bodies determines the weight (or the mass) of a planet. We must somehow measure the strength of its "tug" on another object in order to use gravity to find the mass of a planet. We can harness Newton's equations to deduce what the mass of the planet must be through observing the time it takes for the satellite to orbit its primary planet.

Given:

Mass of Venus = 4.87 x 1024 kg

= 4986.88

Mass of Jupiter = 1.898 x 1024 kg

= 1943.552

Mass of Jupiter compared to mass of Venus

1943.552 / 4986.88

= 0.3897330595482546

= 0.3897330595482546 x 100%

= 38.97%

So, in this problem, <span>the mass of Jupiter is about 0.39 times the mass of Venus.</span>

7 0

4 years ago

The pressure of the earth's atmosphere at sea level is 14.7 lb/in2. What is the pressure when expressed in g/m2? (2.54 cm = 1 in

miss Akunina [59]

<h2>Answer:</h2>

14.7 lb / in² = 10333018.166 g / m²

<h2>Explanation:</h2>

Given from the question;

pressure = 14.7lb/in²

<u>To convert from lb / in² to g / m²</u>

Note;

2.54 cm = 1 in ------------(i)

But;

100 cm = 1m

=> 2.54cm = 2.54 cm x 1 m / 100 cm = 0.0254m

=>2.54cm = 0.0254m

Substitute 2.54cm = 0.0254m into equation(i)

=> 0.0254m = 1 in

2.205 lb = 1 kg ------------------(ii)

But;

1kg = 1000g

Substitute 1kg = 1000g into equation (ii)

=> 2.205 lb = 1000g ---------------------(iii)

<em>From equation(iii);</em>

if, 2.205 lb = 1000g

then, 1 lb = 1 lb x 1000 g / 2.205 lb = 453.5g

=> 1 lb = 453.5 g

<em>Now let's convert 14.7 lb/in² to g / m²;</em>

=> 14.7 lb / in² could be written as 14.7 x 1 lb / (1 in x 1 in)

i.e

=> 14.7 lb / in² = 14.7 x 1 lb / (1 in x 1 in) ------------------(iv)

<em>Substitute the values of 1 lb = 453.5g and 1 in = 0.0254m into equation(iv)</em>

=> 14.7 lb / in² = 14.7 x 453.5g / (0.0254m x 0.0254m)

=> 14.7 lb / in² = 6666.45 g / (0.00064516m²)

=> 14.7 lb / in² = 10333018.166 g / m²

<em>Therefore, 14.7 lb / in² = 10333018.166 g / m²</em>

5 0

4 years ago

2. The water is then heated to its boiling point. Calculate the specific latent heat of

Law Incorporation [45]

Answer:

2465 J/g

Explanation:

The amount of energy required to boil a sample of water already at boiling point is given by

$Q=m\lambda_v$

where

m is the mass of the water sample

$\lambda_v$ is the specific latent heat of vaporization of water

In this problem, we know

$Q=813,600 J$

$m = 330 g$

Solving the equation for $\lambda_v$ , we find

$\lambda_v = \frac{Q}{m}=\frac{813600}{330}=2465 J/g$

6 0

4 years ago

What types of changes effect the sun’s energy output?

Greeley [361]

Answer:

the answer is A Cycles of solar flares and prominences heat and cool the layers below the sun’s surface

Explanation:

i took the quiz

3 0

3 years ago