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lukranit [14]
3 years ago
15

Two vectors A and B are directed such that there is an angle θ between them. show answer Incorrect Answer Which of the following

statements is true about the scalar product of these two vectors?
Physics
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

Scalar product is between ║A║ ║ B║ and  -║A║ ║ B║

Explanation:

Dot product between vec A and vec B is

A.B  = ║A║ ║ B║  cos θ

Here, both ║A║ and ║B║ are positive and value of cos θ depends upon θ  and lies between 1 and -1

So, Scalar product is between ║A║ ║ B║ and  -║A║ ║ B║

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Ways in which a teacher plays a role in the literacy development of the learners​
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Answer:

encourage all attempts at reading, writing, and speaking

Explanation:

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2 years ago
How do the meetings of the words exercise and fitness differ?
ICE Princess25 [194]
Exercise is the activity and fitness is a lifestyle and done with time
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3 years ago
What is the moment of inertia of a 2.0 kg, 20-cm-diameter disk for rotation about an axis (a) through the center, and (b) throug
FinnZ [79.3K]

Answer:

(a) I=0.01 kg.m²

(b) I=0.03 kg.m²

Explanation:

Given data

Mass of disk M=2.0 kg

Diameter of disk d=20 cm=0.20 m

To Find

(a) Moment of inertia through the center of disk

(b) Moment of inertia through the edge of disk

Solution

For (a) Moment of inertia through the center of disk

Using the equation of moment  of Inertia

I=\frac{1}{2}MR^{2}\\  I=\frac{1}{2}(2.0kg)(0.20m/2)^{2}\\  I=0.01 kg m^{2}

For (b) Moment of inertia through the edge of disk

We can apply parallel axis theorem for calculating moment of inertia

I=(1/2)MR^{2}+MD\\ Here\\D=R\\I=(1/2)(2.0kg)(0.20m/2)^{2}+(2.0kg)(0.20m/2)^{2}\\  I=0.03kgm^{2}

8 0
3 years ago
An old grindstone, used for sharpening tools, is a solid cylindrical wheel that can rotate about its central axle with negligibl
krok68 [10]

(a) The moment of inertia of the wheel  is 78.2 kgm².

(b) The mass (in kg) of the wheel is 1,436.2 kg.

(c) The angular speed (in rad/s) of the wheel at the end of this time period is 3.376 rad/s.

<h3>Moment of inertia of the wheel</h3>

Apply principle of conservation of angular momentum;

Fr = Iα

where;

  • F is applied force
  • r is radius of the cylinder
  • α is angular acceleration
  • I is moment of inertia

I = Fr/α

I = (200 x 0.33) / (0.844)

I = 78.2 kgm²

<h3>Mass of the wheel</h3>

I = ¹/₂MR²

where;

  • M is mass of the solid cylinder
  • R is radius of the solid cylinder
  • I is moment of inertia of the solid cylinder

2I = MR²

M = 2I/R²

M = (2 x 78.2) / (0.33²)

M = 1,436.2 kg

<h3>Angular speed of the wheel after 4 seconds</h3>

ω = αt

ω = 0.844 x 4

ω = 3.376 rad/s

Thus, the moment of inertia of the wheel  is 78.2 kgm².

The mass (in kg) of the wheel is 1,436.2 kg.

The angular speed (in rad/s) of the wheel at the end of this time period is 3.376 rad/s.

Learn more about moment of inertia here: brainly.com/question/14839816

#SPJ1

7 0
1 year ago
Which threats of the biodiversity is a result of plants and animals introduced to an ecosystem where they are not normally found
Nezavi [6.7K]
The answer is invasive species. Invasive species is when plants, fungus or animals that are not familiar or native to specific location and has a tendency to spread damage to environment, human health  and human economy. eg: Cane toads are originally from Australia and was moved to grasslands. These toads  are invasive species in Grasslands because they are destroying the environment and destroying the balance of wildlife (in Grasslands).

Invasive species are one of the threats to biodiversity and some ecosystems.

hope this helps
 
7 0
3 years ago
Read 2 more answers
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