Answer: c for the first part
1,6 for the second
nether for the third
Step-by-step explanation:
all on edg
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
he whent up and not down and left and not right
Step-by-step explanation:we just is messed up in life
M+15=65 could this be the answer you are possibly looking for? if the m is Mai's savings "increased by 15" would simply be adding 15 and it would be equal to 65
Not sure how to do it in this form but in slope intercept form for example if the slope was -4/3 the perpendicular would be 3/4 it’s the negative reciprocal of the answer