ANSWER
5
EXPLANATION
The equation that expresses the approximate height h, in meters, of a ball t seconds after it is launched vertically upward from the ground is
To find the time when the ball hit the ground,we equate the function to zero.
Factor to obtain;
Apply the zero product property to obtain,
t=0 or t=5.1 to the nearest tenth.
Therefore the ball hits the ground after approximately 5 seconds.
Using a system of equations, it is found that the third graph shows a pair of lines that represent the equations with a solution (−5, 2).
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
The solution of the system on a graph is the intersection of two lines. The third graph has an intersection at (-5,2), hence it is the answer to this question.
More can be learned about a system of equations at brainly.com/question/24342899
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Answer:
9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;
(x - 2)²/2² - (y + 3)²/3² = 1
Step-by-step explanation:
The standard form of a hyperbola is given as follows;
(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1
The given equation is presented as follows;
9·x² - 36·x = 4·y² + 24·y + 36
By completing the square, we get;
(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)
(3·x - 6)² - 36 = (2·y + 6)²
(3·x - 6)² - (2·y + 6)² = 36
(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1
(3·x - 6)²/6² - (2·y + 6)²/6² = 1
3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1
(x - 2)²/2² - (y + 3)²/3² = 1
The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.
Answer:
C
Step-by-step explanation:
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