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geniusboy [140]

3 years ago

13

Makos goal is to save $42 he currently has $2 and plans to save $18 per week let x represent the number of weeks mako saves mone

y

1 answer:

shutvik [7]3 years ago

3 0

It’s is 3 weeks long that’s the answer

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8. Which statement is always true?

Anit [1.1K]

Answer:

D

Step-by-step explanation:

Any number multiplied by an even number will always be even. 10 is an even number.

4 0

3 years ago

Read 2 more answers

Fractions is greater than 2/5 and less than 3/5?

taurus [48]

Answer:

1/2

Step-by-step explanation:

6 0

3 years ago

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Find the side lengths of the triangle in this picture.

ozzi

Answer:

Hypotenuse: 41 meters, Long leg: 40 meters, Short leg: 9 meters.

Step-by-step explanation:

According to the statement, we have the following information about the lengths of the right triangle:

Hypotenuse

$3\cdot x + 14$

Long leg

$3\cdot x + 13$

Short leg

$x$

By the Pythagoric Theorem, we have the following expression:

$(3\cdot x + 14)^{2} = x^{2} + (3\cdot x + 13)^{2}$ (1)

$9\cdot x^{2}+84\cdot x + 196 = x^{2} + 9\cdot x^{2} + 78\cdot x + 169$

$9\cdot x^{2} + 84\cdot x + 196 = 10\cdot x^{2} + 78\cdot x +169$

$x^{2} -6\cdot x -27 = 0$

$(x-9)\cdot (x+3) = 0$

As length is a positive variable by nature, then the only possible solution is $x = 9$ . Lastly, the side lengths of the right triangle are:

Hypotenuse: 41 meters, Long leg: 40 meters, Short leg: 9 meters.

8 0

3 years ago

Calculus hw, need help asap with steps.

nikdorinn [45]

Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let $f(n) = \frac{(-1)^{n+1}}{n!}$

The summation given to us represents the following

$\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\$

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum $S_1$ is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say $S_1 = f(1) = 1$

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

$S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\$

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

$S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\$

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

$S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\$

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like $S_3 = S_2 + f(3)$ and $S_4 = S_3 + f(4)$

In general, $S_{n+1} = S_{n} + f(n+1)$ so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find $S_5$

$S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333$

The scratch work for f(5) is shown below.

7 0

3 years ago

12x to the power of 5 divided by 3xto the power of 2

meriva

Answer:

the answer for this question is 0.713333333333

5 0

3 years ago