3 years ago

Simplify. Consider all cases. |14−(x−6)| |14−(6-x)|

Mathematics

1 answer:

S_A_V [24]3 years ago

8 0

Answer:

8+x if x > -8

8 if x = 0

-8-x if x < -8

Step-by-step explanation:

|14−(6-x)|

|14−6+x|

|8+x|

8+x if x > -8

8 if x = 0

-8-x if x < -8

You might be interested in

GIVING BRAINLIEST FOR BEST ANSWER!

marusya05 [52]

1/2 - 1/5 - 5 = -47/
10
= -4 7/
10
= -4.7

6 0

2 years ago

Read 2 more answers

Michael spent 4976. We exchange the Kuna she had left for US dollars. The exchange rate was one Kuna two $0.17. How many US doll

PIT_PIT [208]

Well, we need to know how much was money the individual started with.

5 0

2 years ago

Read 2 more answers

Can someone please explain how to find this answer? thanks

N76 [4]

I would start with the standard form equation of the parallel line.
.. 5x -2y = 5(-2) -2(3) = -16
Then solve for y.
.. 2y = 5x +16 . . . add 2y+16; then divide by 2 for the next equation
.. y = (5/2)x +8 . . . . . . . corresponds to selection (B)

6 0

3 years ago

Read 2 more answers

A construction company purchased some equipment costing $300,000. The value of the equipment depreciates

goldfiish [28.3K]

Answer:

$11.9\ years$

Step-by-step explanation:

we know that

The formula to calculate the depreciated value is equal to

$V=P(1-r)^{x}$

where

V is the depreciated value

P is the original value

r is the rate of depreciation in decimal

x is Number of Time Periods

in this problem we have

$P=\$300,000\\r=14\%=14/100=0.14\\V=\$50,000$

substitute the values and solve for x

$50,000=300,000(1-0.14)^{x}$

$(50,000/300,000)=(0.86)^{x}$

$(5/30)=(0.86)^{x}$

Apply log both sides

$log(5/30)=(x)log(0.86)$

$x=log(5/30)/log(0.86)$

$x=11.9\ years$

4 0

3 years ago

Read 2 more answers

a person travels 8 miles due north, 3 miles due west, 7 miles due north and 11 miles due east. how far so the person from the st

PilotLPTM [1.2K]

Answer:

The correct answer would be 7. Explaination below

Step-by-step explanation:

8 + 7 = 15

15 + 3 = 18

18 - 11 = 7

7 0

2 years ago