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3 years ago

To find three consecutive odd integers that have a sum of 63

2 answers:

8 0

Since we are finding the sum of three consecutive odd integers, we will be skipping our even numbers so we can set up an equation.

X + X + 2 + X + 4 = 63

Now, since we have 3 X's on the same side, we can combine them. We can also combine 4 and 2 together to get 6.

<h2>3x + 6 = 63</h2><h2> -6 -6 ← subtract 6 on both sides</h2><h2 /><h2 /><h2>3x = 57</h2><h2>÷3 ÷3</h2><h2 /><h2>X = 19</h2><h2>X + 2 = 21</h2><h2>X + 4 = 23</h2><h2 /><h3>Therefore, our three consecutive odd integers are 19, 21, and 23.</h3>

ludmilkaskok [199]3 years ago

7 0

Three consecutive odd integers that have a sun og 63 would be 23, 11, 29

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Match the expressions with their equivalent simplified expressions.

Tasya [4]

Answer:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}$

Step-by-step explanation:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}$

$\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}$

$\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}$

$\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}$

$\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}$

$\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}$

Thus,

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3 years ago

Find the measure of angle y, 38,41,19

astra-53 [7]

If this is DMS then the answer is 38.68861111 degrees

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2 years ago

How did the temperature change if: at first it decreased by 60% and then increased by 80%. PLEASE NEED HELP!

Sergio039 [100]

The temperature decreased by 28%

Step-by-step explanation:

How did the temperature change if :

At first it decreased by 60%
Then increased by 80%

Assume that the temperature before decreasing is 100%

∵ The temperature before decreasing = 100%

∵ It decreased by 60%

→ Before decreasing : decreasing : after decreasing

→ 100% : 60% : 100% - 60% = 40%

∴ The temperature after decreasing = 40%

Assume that the temperature after decreasing is 100%

∵ The temperature after decreasing = 100%

∵ It increased by 80%

By using the ratio method

→ After decreasing : increasing : after increasing

→ 100% : 80% : 100% + 80% = 180%

→ 40% : : x%

By using cross multiplication

∴ 100% × x% = 40% × 180%

- Divide both sides by 100%

∴ x% = $\frac{(40)(180)}{100}$

∴ x% = 72%

∵ At first the temperature = 100%

∵ At last the temperature = 72%

∵ The first the temperature > the last the temperature

∴ The decreasing in temperature = 100% - 72% = 28%

The temperature decreased by 28%

Learn more:

You can learn more about ratio in brainly.com/question/2707032

#LearnwithBrainly

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