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3 years ago

Translate the word phrase into a variable expression. five more than the product of x and 6

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

8 0

Answer:

6X+5

Step-by-step explanation:

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(xy + 9y + 2) and (xy – 3)

Bezzdna [24]

Answer:

x^2y^2 +9xy^2-xy-27y-6

Step-by-step explanation:

(xy+9y+2) (xy-3)

Each term of second bracket will be multiplied with the terms of first bracket

= xy(xy+9y+2) -3(xy+9y+2)

= x^2y^2+9xy^2+2xy-3xy-27y-6

=x^2y^2+9xy^2-xy-27y-6

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3 years ago

3. 3(2x - 1) + 4 = 3 - 5(1 - x)<br><br>

yarga [219]

Answer:

= -3

Step-by-step explanation:

8 0

3 years ago

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57.8 ÷ 81 (63 points and too lazy to solve the questions but help!)

Luba_88 [7]

0.71358024691

If you are rounding then the answer would be 0.71

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3 years ago

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An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio

olga2289 [7]

Answer:

a) $E(Y) = \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60$

b) $E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1$

And then the expected value would be:

$E(100Y^2) = 100*1.1= 110$

Step-by-step explanation:

We assume the following distribution given:

Y 0 1 2 3

P(Y) 0.60 0.25 0.10 0.05

Part a

We can find the expected value with this formula:

$E(Y) = \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60$

Part b

If we want to find the expected value of $100 Y^2$ we need to find the expected value of Y^2 and we have:

$E(Y^2) = \sum_{i=1}^n Y^2_i P(Y_i)$

And replacing we got:

$E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1$

And then the expected value would be:

$E(100Y^2) = 100*1.1= 110$

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3 years ago

Write the following while number as it’s English word equivalent

ahrayia [7]

Answer:

eight hundred seventy-five thousand six hundred eighty-seven

<em>hope this helps :)</em>

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3 years ago

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