The magnitude of the final velocity of the cue ball is (B) 0.56m/s.
<h3>
What is Velocity</h3>
- The definition of velocity is a vector measurement of the rate and direction of motion.
- It is a moving body's speed and direction of motion.
How to calculate the magnitude of the final velocity?
The magnitude of the final velocity can be calculated by following the steps:
- The mass of the cue ball given is 0.4kg.
- The velocity of the cue ball given is +0.80m/s.
- The velocity of the striped ball before the collision is +0.38 m/s.
- The velocity of the striped ball after collision is +0.62m/s.
- We need to find the magnitude of the final velocity of the cue ball.
Assuming all pool balls have the same mass: 0.4kg
Let the final velocity of the cue ball be x.
Now, To find the final velocity:
- Mass of the cue ball × initial velocity of cue ball + Mass of striped ball + initial velocity of striped ball = mass of cue ball × final velocity + mass of striped ball × final velocity of the striped ball
- (0.40)×(0.80)+(0.4)(0.38) = (0.4)(x)+(0.4)(0.62)
- 0.32+0.152=0.4x+0.248
- 0.472=0.4x+0.248
- 0.472-0.248= 0.4x
- 0.224/0.4 =x
- x = 0.56m/s
Therefore, the magnitude of the final velocity of the cue ball is (B) 0.56m/s.
Know more about velocity here:
brainly.com/question/25749514
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The correct question is given below:
In a game of pool, a 0.4 kg cue ball is traveling at +0.80 m/s when it hits a slower striped ball moving at +0.38 m/s. After the collision, the striped ball moves off at +0.62 m/s. What is the magnitude of the final velocity of the cue ball? Assume all pool balls have the same mass.
A. 0.20 m/s
B. 0.56 m/s
C. 1.0 m/s
D. 1.8 m/s
D midpoint of EC -----------------> FD parallel to AC and FD=AC/2=14/2=7
<span>2-EB=EA E midpoint of AB </span>
<span>DB=DC D midpoint BC ...............> ED=AC/2=2 </span>
<span>3-T midpoint of SR </span>
<span>U midpoint of QR ---------> TU = QS/2 </span>
<span>QS=2 TU = 4.4 </span>
<span>4- The same steps SR=2 UV=9 </span>
<span>5-N midpoint of KM </span>
<span>O midpoint of ML </span>
<span>* NO parallel to Kl</span>
<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
I just did this my bad bro
Answer:
(1) 0.125
(2) 0.125
Step-by-step explanation:
The total number of possible outcomes is:
N = 8
(1)
Compute the probability that the number picked is between 3 and 5 as follows:
Number of Favorable outcomes = 1
The probability is:
P (Number picked is between 3 and 5) = 1/8 = 0.125
Thus, the probability that the number picked is between 3 and 5 is 0.125.
(2)
The number usually picked appears to be in in the range [3,5], i.e. the numbers could be, {3, 4 or 5}.
Number of Favorable outcomes = n (Number < 4 and within [3, 5]) = 1
P (less than 4 ∩ within [3, 5]) = 1/8 = 0.125
Thus, the probability that the number picked is less than 4 knowing that the number usually picked appears to be in in the range [3,5] is 0.125.
