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Ivanshal [37]
3 years ago
13

If a equals 10 feet, B equals 6B, C equals 1 foot, D equals 14 feet, and E equals 2 feet, what is the area of the object?

Mathematics
1 answer:
lutik1710 [3]3 years ago
7 0
I think it may be 1,680B but I'm not too sure...
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Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
2 years ago
What is the rule when multiplying or dividing by a negative number to solve inequalities?
Alika [10]
You flip the inequality.
Example: if x > -y and you divide both sides by (-1) then you flip the inequality so: -x < y
4 0
3 years ago
Read 2 more answers
Someone help me please !!!
KIM [24]

Answer:

1. 10

2. 12

3. Sqrt 130

4. Sqrt 45

Step-by-step explanation:

To find the missing side of a right triangle, use the Pythagorean Theorem. The Pythagorean Theorem is a^2+b^2=c^2 where a and b are the legs with a being the smallest and c is the hypotenuse.

1. a=6, b=8, c=?

6^2+8^2=c^2\\36+64=c^2\\100=c^2\\10=c

2. a=5, b=?, c=13

5^2+b^2=13^2\\25+b^2=169\\169-25=b^2\\144=b^2\\12=b

3. a=7, b=9, c=?

7^2+9^2=c^2\\49+81=c^2\\130=c^2\\\sqrt{130}=c

4. a=2, b=?, c=7

2^2+b^2=7^2\\4+b^2=49\\49-4=b^2\\45=b^2\\\sqrt{45}=b

5 0
3 years ago
2. (02.01 LC)<br> 2x - 20<br> Solve:<br> 2x = 20<br> = 2x
Lubov Fominskaja [6]
The answer is x = 10
6 0
2 years ago
:(:(:(:(:(:(:(:(:(:(:(:(::(
frosja888 [35]

Answer:

12

Step-by-step explanation:

Let's simplify each term.

(\frac{1}{4})^{2} = 0.0625

4^{3} =64

(4-1) = 3

Now we multiply:

0.0625*64*3 = 12

Hope this helps!

3 0
2 years ago
Read 2 more answers
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