Answer:
102
Step-by-step explanation:
You have to substitute x and y. Since x = 3 and y = 4, you would write the equation as 6(3) + 21(4). Multiply that, and you get 18 + 84. Add that together, and you get the answer 102.
1.5
first there is one four in a six which gives you 1
and then 2/4 is 1/2 which u 0.5
add them and you get 1.5
Answer:
£8.58
Step-by-step explanation:
£26 x 0.33 = £8.58
Answer:
1= 36
2= 6
3= 42
4= 162
5= 200
Step-by-step explanation:
Complete Question:
a) Is it plausible that X is normally distributed?
b) For a random sample of 50 such pairs, what is the (approximate) probability that the sample mean courtship time is between 100 min and 125 min?
Answer:
a) It is plausible that X is normally distributed
b) probability that the sample mean courtship time is between 100 min and 125 min is 0.5269
Step-by-step explanation:
a)X denotes the courtship time for the scorpion flies which indicates that is a real - valued random variable, and since normal distribution is a continuous probability distribution for a real valued random variable, it is plausible that X is normally distributed.
b) Probability that the sample mean courtship time is between 100 min and 125 min
![\mu = 120\\n = 50](https://tex.z-dn.net/?f=%5Cmu%20%3D%20120%5C%5Cn%20%3D%2050)
![P(x_{1} < \bar{X} < x_{2} ) = P(z_{2} < \frac{x_{2}- \mu }{SD} ) - P(z_{1} < \frac{x_{2}- \mu }{SD})](https://tex.z-dn.net/?f=P%28x_%7B1%7D%20%20%3C%20%5Cbar%7BX%7D%20%3C%20x_%7B2%7D%20%29%20%3D%20P%28z_%7B2%7D%20%20%3C%20%5Cfrac%7Bx_%7B2%7D-%20%5Cmu%20%7D%7BSD%7D%20%29%20-%20P%28z_%7B1%7D%20%20%3C%20%5Cfrac%7Bx_%7B2%7D-%20%5Cmu%20%7D%7BSD%7D%29)
![SD = \sqrt{\frac{\sigma^{2} }{n} } \\SD = \sqrt{\frac{110^{2} }{50} } \\SD = 15.56](https://tex.z-dn.net/?f=SD%20%3D%20%5Csqrt%7B%5Cfrac%7B%5Csigma%5E%7B2%7D%20%7D%7Bn%7D%20%7D%20%5C%5CSD%20%3D%20%5Csqrt%7B%5Cfrac%7B110%5E%7B2%7D%20%7D%7B50%7D%20%7D%20%5C%5CSD%20%3D%2015.56)
![P(100 < \bar{X}](https://tex.z-dn.net/?f=P%28100%20%3C%20%5Cbar%7BX%7D%20%3C125%20%29%20%3D%20P%28z_%7B2%7D%20%20%3C%20%5Cfrac%7B125-%20120%20%7D%7B15.56%7D%20%29%20-%20P%28z_%7B1%7D%20%20%3C%20%5Cfrac%7B100-%20120%20%7D%7B15.56%7D%29%5C%5CP%28100%20%3C%20%5Cbar%7BX%7D%20%3C125%20%29%20%3D%20P%28z_%7B2%7D%20%20%3C%200.32%20%29%20-%20P%28z_%7B1%7D%20%20%3C%20-1.29%29)
From the probability distribution table:
![P(z_{2} < 0.32 ) = 0.6255\\ P(z_{1} < -1.29) = 0.0986](https://tex.z-dn.net/?f=P%28z_%7B2%7D%20%20%3C%200.32%20%29%20%3D%200.6255%5C%5C%20P%28z_%7B1%7D%20%20%3C%20-1.29%29%20%3D%200.0986)
![P(100 < \bar{X}](https://tex.z-dn.net/?f=P%28100%20%3C%20%5Cbar%7BX%7D%20%3C125%20%29%20%3D%200.6255%20-%200.0986%5C%5CP%28100%20%3C%20%5Cbar%7BX%7D%20%3C125%20%29%20%3D0.5269)