Question

Jessica bought 3/4 lb of berries. Mary bought 1/6 lb of berries less the jessica. what is the total weight of berries in pounds that they bought?? Need Help ASAP!!!

Answer 1

Given that number of pounds of berries that Jessica bought = $\frac{3}{4}$ lb

Given that "Mary bought $\frac{1}{6}$ lb of berries less the jessica"

then number of pounds of berries that Mary bought

$=(\frac{3}{4}-\frac{1}{6})$  lb

$=\frac{3}{4}\cdot\frac{3}{3}-\frac{1}{6}\cdot\frac{2}{2}$  lb

$=\frac{9}{12}-\frac{2}{12}$  lb

$=\frac{7}{12}$  lb

Now we need to find the total weight of berries in pounds that they bought.

To find that we just need to add both values.

$\frac{3}{4}+\frac{7}{12}$

$=\frac{3}{4}\cdot\frac{3}{3}+\frac{7}{12}$

$=\frac{9}{12}+\frac{7}{12}$

$=\frac{16}{12}$

$=\frac{4}{3}$

Hence final answer is $\frac{4}{3}$ lb.