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irinina [24]
3 years ago
6

Sarah bought a binder for $7.25 and six folders that totaled $9.05 how much did each folder cost

Mathematics
2 answers:
nekit [7.7K]3 years ago
8 0
$9.05-$7.25=1.8 then $1.8/6=$0.3. Answer is $0.3
creativ13 [48]3 years ago
4 0

Answer:

Each binder costs 30 cents or $0.30

Step-by-step explanation:

If Sarah's total was $9.05 and the binder costs 7.25 then in order to find the price of the folders you must subtract the cost of the binder (7.25) from the total (9.05) which leaves $1.80 as the amount she paid in total for 6 folders. Next, to find the amount spent per folder divide 1.80 by the number of folders which is 6 and your final answer should be 0.30.

9.25= 7.25+6x (next subtract 7.25 on both sides)

1.80=6x (next divide by six on both sides)

0.30=x

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Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En
ArbitrLikvidat [17]

Answer:

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, c) x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right), y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right).

Step-by-step explanation:

The equation of the circle is:

x^{2} + (y-1)^{2} = 16

After some algebraic and trigonometric handling:

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t

Where:

\frac{x}{4} = \cos t

\frac{y-1}{4} = \sin t

Finally,

x = 4\cdot \cos t

y = 1 + 4\cdot \sin t

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

c) x = 4\cdot \cos t'', y = 1 + 4\cdot \sin t''

Where:

4\cdot \cos t' = 0

1 + 4\cdot \sin t' = 5

The solution is t' = \frac{\pi}{2}

The parametric equations are:

x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right)

y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)

7 0
3 years ago
In triangle ABC, angle = 90 degrees. AC = 7, BC = 12. AB = _______ Measure of angle A = _______ Measure of angle B = _______
Ulleksa [173]

Answer:

AB = 13.89

Measure of angle A = 59.74°

Measure of angle B = 30.26°

Step-by-step explanation:

The given parameters are;

∠C = 90°

AC = 7

BC = 12

Part 1

Hence, the question has the dimensions of the two adjacent sides of the right angle (angle 90°)

From Pythagoras theorem, we have;

A² = B² + C²

Where, A is the opposite side to the right angle, hence;

In the ΔABC,

AB ≡ A

Therefore;

AB² = AC² + BC² = 7² + 12² = 193

∴ AB = √193 = 13.89

Part 2

∠A is the side opposite side BC such that by trigonometric ratios

tan \angle A = \frac{Opposite \, side \,  to \,  angle \,  A}{Adjacent  \,  side  \, to  \, angle \,  A}  = \frac{BC}{AC} = \frac{12}{7} = 1.714

∴ ∠A = Arctan(1.714) or tan⁻¹(1.714) = 59.74°

Part 3

∠B is found from knowing that the sum of the angles in a triangle = 180°

∴ ∠A + ∠B + ∠C = 180° which gives

59.74° + 90° + ∠B = 180°

Hence, ∠B = 180° - (59.74° + 90°) = 180° - 149.74° = 30.26°.

7 0
3 years ago
Read 2 more answers
Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unknown
kiruha [24]

Answer:

The other endpoint is (-33, 17)

Step-by-step explanation:

The rule of the mid-point of a segment whose endpoints are

(x_{1}, y_{1}) and (x_{2}, y_{2}) is

  • (x_{M},y_{M})  = (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

In our question

∵ The coordinates of the endpoints of a segment are (-15, 13) and (x, y)

∴ x_{1} = -15 and x_{2} = x

∴ y_{1} = 13 and y_{2} = y

∵ The coordinates of the mid-point of this segment are (-24, 15)

∴ x_{M} = -24 and y_{M} = 15

→ Use the rule of the mid-point to find x and y

∵ -24=\frac{-15+x}{2}

→ Multiply both sides by 2

∴ -48 = -15 + x

→ Add 15 to both sides

∴ -33 = x

∵ 15=\frac{13+y}{2}

→ Multiply both sides by 2

∴ 30 = 13 + y

→ Subtract 13 from both sides

∴ 17 = y

∴ The other endpoint is (-33, 17)

5 0
3 years ago
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slavikrds [6]

Answer:

A. 0.4

B.0.9

C.0.7

Step-by-step explanation:

5 0
3 years ago
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Ayanna plans to bake 3 types of cookies to take to a party. She needs to be sure that she has enough flour. The chocolate cookie
djyliett [7]
The children brought 2+1+114=414 cups of flour and 14+12+34=112 cups of butter.

They have enough flour for

414÷34===174×43173523
batches and they have enough butter for

112÷13===32×3192412
batches, so the butter is the limiting factor. Thus, they can make 4 whole batches of a dozen cookies each.
7 0
3 years ago
Read 2 more answers
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