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3 years ago

Find the sum of the arithmetic series for which a_1 = 7, n = 31, and a_n = 127.

Mathematics

1 answer:

uranmaximum [27]3 years ago

8 0

Answer: 2077

There are 31 terms.

S₃₁ = 31(a₁+a₃₁)/2 = 31(7+127)/2 = 2077

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Tresset [83]

Answer:

x axis

Step-by-step explanation:

We know the x value stays the same. If you were to graph the line y=3 and y=-3, you would see that it is a reflection over the x axis.

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2 years ago

A function is blank a relation *always *sometimes *never

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Answer:

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3 years ago

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

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2 years ago

Two boats start their journey from the same point A and travel long directions AC and AD as shown below what is the distance CD

Olegator [25]

I think its B but ima have to check again and get back to you

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3 years ago

Read 2 more answers