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AVprozaik [17]
3 years ago
15

For (x - 1)(x - 7) to equal 0, either (x - 1) or (x - 7) must equal what?

Mathematics
1 answer:
Kisachek [45]3 years ago
8 0
(x - 1)(x - 7) = 0

{x}^{2} - 8x + 7 = 0

{x}^{2} - 8x = - 7

- 7x = \frac{ - 7}{x}

x = \frac{ - 7}{ \frac{x}{ - 7} } \implies x = x \implies x \in \mathbb{R}

x is true for any number in real domain.
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Diversification means that you invest in _____.
kupik [55]
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If you need me to corect this answer, I'd be more than happy to. <3
7 0
3 years ago
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Find the distance between the two points rounding to the nearest tenth (if necessary). (2,−3) and (0,−8)
saveliy_v [14]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.
Tema [17]

Answer:

Area  \approx 1149\ cm^2

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to \angle W)

Side u = 83 cm (It is the side opposite to \angle U)

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

A = \dfrac{1}{2}\times a\times b\times sinC

Where a and b are the two sides and

\angle C is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A  \approx 1149\ cm^2

So, the <em>area </em>of given triangle to the nearest square centimetre is:

Area  \approx 1149\ cm^2

8 0
4 years ago
10 more than the quotient of c and 3
Katen [24]

10 +  \frac{c}{3}

4 0
3 years ago
What is the solution set for 6x−9=15, given the replacement set {0, 1, 2, 3, 4}?
vfiekz [6]
6x-9=15
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Hope this helps :)
6 0
3 years ago
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