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3 years ago

HELPPPP!!!!

Mathematics

1 answer:

Tamiku [17]3 years ago

8 0

Answer:

A. 7.87 cups for 5½ loads

B. 3.93 cups for the tiny loaf

Step-by-step explanation:

A. 5.25 divide by 2 = 2.62 (rounded)

5.25 + 2.62 = 7.87

B. 5.25 × 0.75 = 3.93 cups

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The endpoints of VW are V(-4,9) and W(1,-6). Find the coordinates of the midpoint M

elena-14-01-66 [18.8K]

Answer:

(-3/2 or 1.5, 3/2 or 1.5)

x = -3/2 or -1.5

y = 3/2 or 1.5

Step-by-step explanation:

the midpoint formula is x1+x2/2 and then y1+y2/2 so -4 +1 = -3/2 for x. for y, 9 + -6 = 3/2. so the midpoint would be (-3/2 or 1.5, 3/2 or 1.5) depending on if you’re using decimals or fractions

8 0

3 years ago

If 8 out of 20 students in a class are boys,what percent of the class is made up of boys

lara31 [8.8K]

Answer:

40%

Step-by-step explanation:

First, divide 100 by 20. You do this because you need something out of 100 to equal a percent. (Example- 50 out of 100 is 50%)

Next you need to take the number you got from dividing (5) and multiply that with 8. This leaves you with 40/100 or 40%.

Hope this helps!

-Coconut;)

3 0

3 years ago

Can someone help me out

Sophie [7]

Firstly, you want to multiply (f^4)^2. $\frac{2*f^8*f^2}{8f^{12}}$

Next, multiply everything on the numerator. $\frac{2f^{10}}{8f^{12}}$

Next, divide. $\frac{2f^{10}}{8f^{12}}=\frac{1}{4} f^{-2}$

Now remember that f^-2 = (1/f^2), so just convert the negative powered exponent to that, and your answer will be $\frac{1}{4f^2}$

6 0

3 years ago

Find a cartesian equation for the curve and identify it. r = 10 tan(θ) sec(θ)

Vilka [71]

For a cartesian equation
$x=r\cos\theta \ and \ y=r\sin\theta \\ \\ \cos\theta=\frac{x}{r} \ and \ \sin\theta=\frac{y}{r} \\ \\ \tan\theta=\frac{\sin\theta}{\cos\theta}=\frac{y}{r}\cdot\frac{r}{x}=\frac{y}{x} \\ \\ \sec\theta=\frac{1}{\cos\theta}=\frac{r}{x}$

Given r = <span>10 tan(θ) sec(θ)
$r=10\tan\theta\sec\theta=10\cdot\frac{y}{x}\cdot\frac{r}{x} \\ \\ \Rightarrow10y=x^2 \\ \\ \Rightarrow y= \frac{1}{10} x^2$

Therefore,</span>the curve is a parabola opening upward with vertex (0, 0).

3 0

3 years ago

1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides

salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = $\int\limits^1_0 {(e^x-x)} \, dx$

= $\int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx$

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0

2 years ago