1. Points that lie on the intersection area of the inequalities are solutions.
For example (0,2), (-4,4), (2,-1), (-8,0) and all others which lie in this area.
2 Not solutions are points that are on the lines (because we have signs > and <, not ≤ and ≥), or on the areas that are not intercepted. For example, (6,2), (2,2), (2,-4),(-6,-2).
Answer:
See attached
Step-by-step explanation:
In the questions, find the equation of the dash line then apply the appropriate inequality sign.
In the first one, take points (-3,2) and (0,1) find the gradient and slope of the line.
slope of line, m=Δy/Δx
Δy=1-2=-1
Δx= 0--3=3
m= -1/3
Finding the equation of the line;
y-1/x-0 = -1/3
3y-3 =-x
3y=-x+3
y=-1/3 x+1
The inequality can be ;
y> -1/3 x +1 or y<-1/3 x +1 depending on the shaded region as attached
In 2.
You have two graphs that provide the solution of the inequality.
In the graph represented by line 1, where you have points (-3,-4) and (-5,-5)
The slope will be,
m=-5--4/-5--3
m=-5+4/-5+3
m=-1/-2 = 1/2
The equation will be;
y--4/x--3= 1/2
y+4/x+3= 1/2
2y+8=x+3
2y=x+3-8
2y=x-5
y=1/2x -2.5
In the line with points (-3,-4) and (1,-6)
m=-6--4/1--3
m=-6+4/1+3
m=-2/4 = -1/2
Finding the equation of the line
y--4/x--3 = -1/2
2(y+4) = -1 (x+3)
2y+8 =-x-3
2y=-x-3-8
2y=-x-11
y= -1/2x-5.5
The inequality can be ;
y>1/2x + 2.5
y> -1/2x -5.5
or
y< 1/2 x +2.5
y< -1/2x-5.5
Depending on the area shaded as show in the attached graphs
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Keywords : Inequalities, graph solutions
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Answer:800
Step-by-step explanation:
and
Using Z table to get InvNormal(0.9893)=2.30