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3 years ago

Write an expression that represents the product of q and 4÷ 5

Mathematics

1 answer:

laiz [17]3 years ago

7 0

Q=20

~~~~Ella~~~~~ maybe I think

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What is the angle of rotation from MKJ/ to MKJ/? Assume that the center of rotation is the origin.

Dmitry [639]

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3 years ago

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36-9 divided [(0.24*5)+ (0.66*5)]

Ray Of Light [21]

[(0.24*5)+ (0.66*5)] == 4.50
0.24x5 = 1.20
0.66x5 = 3.30
+ ____
4.50

27.00÷4.5 = 0.166666667

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3 years ago

What is the amount of sales tax charged on the repaired computer at Store A?

Softa [21]

Answer:

The answer is 1. $72

Step-by-step explanation:

U can type in a calculator 6% of 1,200 or u can multiply 0.06 by 1,200 :)

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3 years ago

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A store charges a restocking fee for any returned item based upon the item price. An item priced at $200 has a fee of $12. An it

lyudmila [28]

Answer:

Both ratios reduce to the same ratio 3/50, so the restocking fee is proportional.

Step-by-step explanation:

For the $200, the restocking fee is $12, so the ratio of the restocking fee to the price of the item is 12/200.

For the $150, the restocking fee is $9, so the ratio of the restocking fee to the price of the item is 9/150.

Now we find out if the ratios 12/200 and 9/150 are equal.

12/200 = 3/50

9/150 = 3/50

Both ratios reduce to the same ratio 3/50, so the restocking fee is proportional.

7 0

2 years ago

Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec

expeople1 [14]

Answer:

$cot x = \frac{cos x}{sin x}$

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

$cos x cot x + sin x$

We know from math properties that the definition for cot is $cot x = \frac{cos x}{sin x}$

If we use this definition we got:

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

Now we can use the following identity:

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

4 0

3 years ago