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Korolek [52]
3 years ago
11

Interstate 285 around Atlanta is 63.98 mi and is about 80. ft across both directions of traffic. If there are 2.5 inches of snow

(Kf = 1.86 °C/m, density = 0.150 g/cm3) accumulated on the interstate, how many metric tons of CaCl2 are required to alter the freezing point from 32 degrees F to 21 degreesF? ( 1 mi = 1609.34 m, 2.54 cm = 1 in, 12 in = 1 ft, 1000 kg = 1 metric ton)
Chemistry
1 answer:
Burka [1]3 years ago
7 0
<span>12 in = 1 ft.  I hope u find this helpful</span>
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3 years ago
A cylindrical piece of metal is 4.5 dm in height with radius of 5.50 x 10^-5 km.
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Answer:

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Hello,

a) In this case, the given height in cm is:

h=4.5dm*\frac{1m}{10dm}* \frac{100cm}{1m}=45cm

And the radius in cm is:

r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{100cm}{1m}=5.5cm

Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:

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b) In this case, the given height in mm is:

h=4.5dm*\frac{1m}{10dm}* \frac{1000mm}{1m}=450mm

And the radius in mm is:

r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{1000mm}{1m}=55mm

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Best regards.

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