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stepladder [879]
3 years ago
14

In the desert, wind picks up and carries fine particles of sand and dirt. As 5 points

Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

C

It’s wrong I need points

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Ionic bonds •ionic bonds form between ______________ and _________________. •in naming simple ionic compounds, the ____________
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metal, non-metal
water
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6 0
4 years ago
The basic fact that determines molecular shapes is that
Alinara [238K]

Answer:

The shape of a molecule is mostly determined by repulsion among the pairs of electrons around a central atom.

4 0
3 years ago
What is the concentration of an hbr solution if 12.0 ml of the solution is neutralized by 15.0 ml of a 0.25 m koh solution?
Snowcat [4.5K]
The balanced equation for the reaction between KOH and HBr is as follows;
KOH + HBr --> KBr + H₂O
stoichiometry of KOH to HBr is 1:1
number of KOH moles reacted - 0.25 mol/L x 0.015 L = 0.00375 mol
according to molar ration 
number of KOH moles reacted = number of HBr moles reacted 
number of HBr moles reacted - 0.00375 mol 
if 12 mL of HBr contains - 0.00375 mol 
then 1000 mL of HBr contains - 0.00375 mol / 12 mL x 1000 mL = 0.313 mol
therefore molarity of HBr is 0.313 M
4 0
3 years ago
Acetonitrile major species present when dissolved in water
IrinaVladis [17]

Acetonitrile refers to the chemical compound exhibiting the formula CH₃CN. It is the basic organic nitrile and a colorless liquid. It is generated primarily as a byproduct of acrylonitrile production. It is used as a polar aprotic solvent in the purification of butadiene and in organic synthesis.  

The addition of water to cyanides generates amines and acids. Acetonitrile produces ammonia and acetic acid.  

CH₃CN (acetonitrile) → CH₃COOH (acetic acid) + NH₃ (ammonia)


3 0
3 years ago
Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha
Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles

The chemical equation for the reaction of NaI and lead chlorate follows:

Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = \frac{1}{2}\times 0.04=0.02mol of lead iodide

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g

Hence, the mass of lead iodide produced is 9.22 grams

6 0
3 years ago
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