Answer:
Oxygen and Magnesium together, OMg?!?!
<span>1) osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant r.
Call: P = osmotic pressure; C = molarity; T = absolute temperature
=> P = C * T * r
2) </span><span>write an equation that will let you
calculate the molarity c of this solution. your equation should contain
only symbols. be sure you define each symbol other than r.
</span><span>
</span>=> C = P / (rT)
Answer: C = P / (rT)
Answer:
Part A. The half-cell B is the cathode and the half-cell A is the anode
Part B. 0.017V
Explanation:
Part A
The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).
So, the half-cell B is the cathode and the half-cell A is the anode.
Part B
By the Nersnt equation:
E°cell = E° - (0.0592/n)*log[anode]/[cathode]
Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.
E°cell = 0 - (0.0592/2)*log(0.23/0.87)
E°cell = 0.017V
