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Anna11 [10]
3 years ago
13

Farrah needs an electrician and must decide between 2 companies. For a service visit, Company A charges $50 to send an electrici

an plus $40/h. Company B charges $60 to send an electrician plus $36/h. The graph that models this situation is shown here.
According to the graph, how long must each electrician work in order for the two to charge equal amounts?
Mathematics
2 answers:
ss7ja [257]3 years ago
4 0
Company B. Its kinda commen sense.
weqwewe [10]3 years ago
3 0
Each line represents a technician. So if you want to know at what time the charges are equal, you need to see where the lines intersect. In this case, its 2.5 hours. 
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Television sets cost $359 each. The total cost in dollars of five television sets will be measured in the .
romanna [79]
A. thousands. It is because you just have to multiply 5 and 359 so that becomes 1830. So the price of the 5 TV sets will be measured in thousands
5 0
3 years ago
Read 2 more answers
Canadians who visit the United States often buy liquor and cigarettes, which are much cheaper in the United States. However, the
victus00 [196]

Answer:

Probability of bringing a bottle of liquor into the country that is, the probability of bringing 1 bottle liquor into the country = P(B) = 0.31

The probability of not bringing a bottle of liquor into the country, that is, the probability of bringing 0 bottle liquor into the country = P(B') = 0.69

Probability distribution of bottle liquor

Let X represent the random variable of the number of bottle liquor brought into the country by a person

X | P(X)

0 | 0.69

1 | 0.31

Step-by-step explanation:

The joint probability distribution for the number of bottles of liquor and the number of cartons of cigarettes imported by Canadians who have visited the United States for 2 or more days is given in the question as

V | B

C | 0 | 1

0 | 0.62 | 0.16

1 | 0.07 | 0.15

Note that B = bottle liquor

C = Carton cigarettes

V is each variable

Let the probability of bringing a bottle of liquor into the country be P(B), that is, the probability of bringing 1 bottle liquor into the country.

The probability of not bringing a bottle of liquor into the country is P(B'), that is, the probability of bringing 0 bottle liquor into the country.

Let the probability of bringing a carton of cigarettes into the country be P(C), that is, the probability of bringing 1 carton cigarettes into the country.

The probability of not bringing a carton of cigarettes into the country is P(C'), that is, the probability of bringing 0 carton cigarettes into the country.

From the joint probability table, we can tell that

P(B n C) = 0.15

P(B n C') = 0.16

P(B' n C) = 0.07

P(B' n C') = 0.62

Find the marginal probability distribution of the number of bottles imported.

Probability of bringing a bottle of liquor into the country that is, the probability of bringing 1 bottle liquor into the country = P(B)

P(B) = P(B n C) + P(B n C') = 0.15 + 0.16 = 0.31

The probability of not bringing a bottle of liquor into the country, that is, the probability of bringing 0 bottle liquor into the country = P(B')

P(B') = P(B' n C) + P(B' n C') = 0.07 + 0.62 = 0.69

Probability distribution of bottle liquor

Let X represent the random variable of the number of bottle liquor brought into the country by a person

X | P(X)

0 | 0.69

1 | 0.31

Hope this Helps!!!

8 0
3 years ago
6th grade math help me please! :))
finlep [7]

Answer:

672 phone calls is the correct answer

5 0
3 years ago
Read 2 more answers
Find the exact value of the trigonometric expression given that sin(u) = -(3/5),
GuDViN [60]

Recall that

\cot(u+v)=\dfrac{\cos(u+v)}{\sin(u+v)}=\dfrac{\cos u\cos v-\sin u\sin v}{\sin u\cos v+\cos u\sin v}=\dfrac{\cot u\cot v-1}{\cot v+\cot u}

Also, recall that for all \theta,

\cos^2\theta+\sin^2\theta=1

With \frac{3\pi}2, we can expect \cos u>0, and with 0, \sin v>0. So from the above identity it follows that

\cos u=\sqrt{1-\sin^2u}=\dfrac45\implies\cot u=\dfrac{\cos u}{\sin u}=-\dfrac43

and

\sin v=\sqrt{1-\cos^2v}=\dfrac8{17}\implies\cot v=\dfrac{\cos v}{\sin v}=\dfrac{15}8

and so

\cot(u+v)=\dfrac{-\frac43\frac{15}8-1}{\frac{15}8-\frac43}=\boxed{-\dfrac{84}{13}}

6 0
3 years ago
In a 30-60-90 triangle, the length of the side opposite the 30 degree angle is 8. Find the length of the side opposite the 60 de
nalin [4]

Answer:

The length of the side opposite the 60 degree angle 'c' = 4

Step-by-step explanation:

<u>Step(i)</u>:-

Given data ∠A = 90° , ∠B = 60° and ∠C = 30°

Given data the length of the side opposite the 30 degree angle is 8

let  'a' = 8

<u><em>step(ii)</em></u>:-

<em>By using sine rule formula in properties of triangle</em>

<em></em>\frac{a}{Sin A} = \frac{b}{Sin B} = \frac{c}{Sin C} = 2 R<em></em>

<em></em>\frac{a}{Sin A}  = \frac{c}{Sin C}<em></em>

\frac{8}{Sin 90}  = \frac{c}{Sin 30}

cross multiplication , we get

\frac{8 X sin 30}{Sin 90}  = c<em></em>

<em>we know that trigonometry formulas</em>

<em>sin 30° = </em>\frac{1}{2}<em>   and sin 90°= 1</em>

<em>C =  8 X 1/2 = 4</em>

<u><em>conclusion</em></u>:-

<em>The length of the side opposite the 60 degree angle 'c' = 4</em>

<em></em>

3 0
3 years ago
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