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tangare [24]
3 years ago
12

Find the limit for this function

Mathematics
1 answer:
Wewaii [24]3 years ago
5 0
Let pi/2 - x = y , cosx = siny , when x approaches pi/2 , y approaches 0

lim    ((e^siny - 1)/siny) (siny / y)

y-->0

= lne * 1 = 1

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CALLING EXPERTS!!! PLEASE HELP
disa [49]
The circle is open if the inequality is greater than (>) or less than (<) and closed if the inequality is greater than or equal to (≥) or less than or equal to (≤)
If the arrow points to the right (—>) towards bigger numbers, x (whatever number is on the line) will be GREATER (> or ≥)
If the arrow o points to the left (<—) towards smaller numbers, x will be LESSER (< or ≤)

1. Starts at -2 with a closed circle and goes in the positive direction —>
So x ≥ -2
2. Starts at 2 with an open circle and goes in the negative direction <—
So x<2

And the rest use the same method.
6 0
3 years ago
Read 2 more answers
Please help quick!!<br>​
Nataly [62]

Hi !

∫ \frac{t}{t + 1}dt

We need to prove that it is equal to

∫ \frac{u - 1}{u}du

As per given options, Substitute <em>u</em> by <em>t</em><em>+</em><em>1</em><em> </em>

=  > ∫ \frac{u - 1}{t + 1} du

<em>Then</em><em> </em><em>given</em><em> </em><em>t</em><em> </em><em>=</em><em> </em><em>u</em><em>-</em><em>1</em>

=  > ∫ \frac{t}{t + 1} du

Then substitue the third given value also

=  > ∫ \frac{t}{t + 1} dt

Therefore, it's <u>proved</u>

~<em>Hop</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em>s</em>

7 0
2 years ago
How do you multiply fractions?
ser-zykov [4K]
All you do is multiply across. For example...
1/3 x 2/5
Multiply the numerators and denominators.
(1 x 2) / (3 x 5)
= 2/15
If you need to, you can simplify but in this case you don't have to.
I hope this helps love! :)
8 0
3 years ago
Read 2 more answers
Giải các Phương Trình Nghiệm Nguyên <br> 1/x +1/y = 1/6xy
Eddi Din [679]

Answer:

sucky my ducky ;))))

Step-by-step explanation:

5 0
3 years ago
PRE-CAL HELP PLEASE (see attachment)
lana66690 [7]
Answer:


\lim_{x \to \infty} \frac{2500 + 17(x-100)}{x}=17

Explanation:


1) Charges are:

Flat fee: 500
First 100 tickets: 20(100) = 2000
Tickets over 100: 17 ( x - 100), where x is the number of tickets.

2) Total charges: 500 + 2000 + 17(x - 100) = 2500 + 17(x - 100)

3) Average cost per ticket = total charges / number of tickets

⇒ [2500 + 17(x - 100) ] / x


4) limit as the number of tickets, x, becomes very high ⇒ x → ∞

⇒           \lim_{x \to \infty}  \frac{2500 + 17(x-100)}{x}

5) And the value of that limit is equal to 17, as shown below:


2500 / x + 17x / x - 1700/x = 0 + 17 + 0 = 17
8 0
3 years ago
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