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weqwewe [10]
3 years ago
9

What is the equation for f(x)

Mathematics
1 answer:
Paraphin [41]3 years ago
3 0
F(x) = -5/6x - 3

You can get this by identifying the y-intercept and then using the formula for slope given any two points on the graph. 
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Which binomial is a factor of 9x^2+24xy+16y^2
gregori [183]

Answer: (3x + 4y)(3x + 4y)

Step-by-step explanation: So you are supposed to "unfoil". So you would find two numbers multiplied together to make 9x^2 which would be 3x. Then you would find two numbers that can be multiplied together to get 16y^2 which would be 4y. To check your work, you do 3x times 3x. Then 4y times 4y. Then 4y times 3x plus 3x times 4y. You get 9x^2 + 24xy plus 16y^2.

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Greatest common factor 10b^2 and 4a^3
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If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000
zavuch27 [327]

Answer:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

X \sim N(100000,20000)  

Where \mu=100000 and \sigma=20000

We are interested on this probability

P(X>117000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

7 0
3 years ago
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