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Molodets [167]
3 years ago
9

Under a dilation, a figure is enlarged and its orientation is preserved. Choose the statement that best describes the dilation.

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
4 0

Answer: C) The image is along the same ray as the preimage but is closer to the center of dilation.

boyakko [2]3 years ago
3 0
The correct answer of the given question above would be option A. Under a dilation, a figure is enlarged and its orientation is preserved. Based on this, the correct answer statement that best describes the dilation is this: <span>The image is along the same ray as the pre image but is farther from the center of dilation. Hope this answer helps. </span>
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Is 8/10 greater than 3/5
Nutka1998 [239]

Hey!

Is 8/10 greater than 3/5

TRUE because 3/5=6/10

8/10>6/10

Good luck

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He gets 374 miles on 22 gallons.

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I think the correct answer from the choices listed above is the first option. The weight of a gold ring most likely is expressed in ounces. <span>The weight of gold is measured in troy ounces (1 troy ounce = 31.1034768 grams), but its purity, or "fineness" has been measured in a few different ways: "parts fine," "% gold", and karats.</span>
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What is the slope for each for each line<br><br> y=1/2x-4<br> y=2x-3
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2 years ago
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Find each graph, find (a) AB to the nearest tenth and (b) the coordinates of the midpoint of AB.
Rufina [12.5K]

Answer: AB≈10,8,  C(-1;0,5).

Step-by-step explanation:

4.

(-2,-2)\ \ \ \ (8,-6)\ \ \ \  \overline {AB}=?\\

                     Equation of a straight line

                  \boxed {\overline {AB}=\sqrt{(x_B+x_A)^2+(y_B-y_A)^2} }

x_A=-2\ \ \ \  x_B=8\ \ \ \ y_A=-2\ \ \ \ \ y_B=-6\\\\\overline{AB}=\sqrt{(8-(-2))^2+(-6-(-2))^2} \\\\\overline{AB}=\sqrt{(8+2)^2+(-6+2)^2} \\\\\overline{AB}=\sqrt{10^2+(-4)^2} \\\\\overline{AB}=\sqrt{100+16} \\\\\overline{AB}=\sqrt{116} \\\\\overline{AB}\approx10,8.

5.

(-2,-2)\ \ \ \ (0,3)\ \ \ \ the\  midpoint\ C\  of\ AB=?\\

                                 Line Midpoint Equation

                           \boxed {C_x=\frac{X_A+X_B}{2} }}\ \ \   \boxed {C_y=\frac{Y_A+Y_B}{2} }

X_A=-2\ \ \ \ \ X_B=0\ \ \ \ \ Y_A==-2\ \ \ \ Y_B=3\\\\C_x=\frac{-2+0}{2} \\\\C_x=\frac{-2}{2} \\\\C_x=-1.\\\\C_y=\frac{-2+3}{2}\\\\C_y=\frac{1}{2}\\\\ C_y=0,5.\\\\Hence,\ \ \  \ C_{AB}(-1;0,5).

                                   

8 0
2 years ago
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