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He will mix some 20% solution and some 70% solution to make 60% solution.
Let x = number of liters of 20% solution.
Let y = number of liters of 70% solution.
He wants to make 50 liters of 60% solution, so
x + y = 50 First Equation
The amount of acid in x amount of 20% solution is 20% of x, or 0.2x
The amount of acid in y amount of 70% solution is 70% of y, or 0.7y
The amount of acid in 50 liters of 60% solution is 60% of 50 liters, or 0.6 * 50 = 30
Now we add the amounts of acid.
0.2x + 0.7y = 30 Second Equation
x + y = 50
0.2x + 0.7y = 30
-0.2x - 0.2y = -10
0.2x + 0.7y = 30
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0.5y = 20
y = 40
x + y = 50
x + 40 = 50
x = 10
Answer: He needs 10 liters of 20% solution and 40 liters of 70% solution.
Hi!
(l = Lenny
m = Max)
Lenny is 3 times as old as Max.
3m = l
When you subtract Max's age from Lenny's age, you get 24.
L - m = 24
Put in the value of l.
3m - m = 24
There is our equation.
Now solve
2m = 24
2m/2 = 24/2
m = 12
3 * 12 = l
36 = l
The equation is 3m - m = 24
Max is 12 and Lenny is 36.
Hope this helps! :)
-Peredhel
Answer:
The statement is true.
Step-by-step explanation:
Let us assume that x is the required number.
Now, given that the number minus 3 is at most 12.
Hence, x - 3 ≤ 12
⇒ x ≤ 15 ......... (1)
And also given that 1 more than 2 times the number is at least 25.
Hence, 2x + 1 ≥ 25
⇒ 2x ≥ 24
⇒ x ≥ 12 .......... (2)
Therefore, from equations (1) and (2) we get the number must be greater than or equal to 12 or less than or equal to 15.
So, the statement is true. (Answer)