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3 years ago

Help please with this worksheet!!!

Mathematics

1 answer:

baherus [9]3 years ago

7 0

Answer:

This is difficult, but I'm here to help.

Bananas to Apples: There is 1 banana to each 1 1/2 of an apple.

How Do You Know: If 1 banana is equal to 1 apple, then 4 bananas are equal to 4 apples. Not enough. Adding 1/2 to each apple, then puts it at 4 bananas equaling 6 apples.

Bananas and Apples to Oranges: 10 bananas and apples to 3 oranges. 5 bananas and apples to 1 1/2 of an orange.

How Do You Know: Try this yourself.

If you can't figure the last one out on your own, tell me. I'll help explain it to you.

You might be interested in

Pls help me i just need number one but u can do 2

torisob [31]

Answer:

1200

Step-by-step explanation:

v=15×8×10

the second one i cant see clearly the number but u just need to multiple tgose two numbers

8 0

3 years ago

Read 2 more answers

Based on a smartphone survey, assume that 58% of adults with smartphones use them in theaters. In a separate survey of 225 adu

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

8 0

3 years ago

Solve each system by substitution.<br> y=-4x-9 y=3x+19

Alekssandra [29.7K]

Answer:

x=-4, y=7

Step-by-step explanation:

According to the first equation, y = -4x - 9, so we can substitute y in the second equation for -4x - 9.

y = 3x + 19

-4x - 9 = 3x + 19

Add 9 to both sides

-4x = 3x + 28

Subtract 3x

-7x = 28

Divide by -7

x = -4

Plugging this into the equation, we have:

y = -4x - 9

y = -4(-4) - 9

y = 16 - 9

y = 7

5 0

2 years ago

The question is below

Digiron [165]

Answer:

(a) Stops, turns around and starts travelling back towards home.

(b) 8 km/hour.

Step-by-step explanation:

(b) Jo travels 4 kilometres in 1/2 hour = 9 km/hour.

8 0

3 years ago

Read 2 more answers

A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum

Ivan

Answer:

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solution

$y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solving the differential equation

$\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}$

Initial conditions:

$y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

$y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48$

The rumor reaches 80% at 8.48 days.

8 0

3 years ago