Answer:
9,000 is the answer you are looking for
Answer:
eeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
eeeeeeeeeeeeeeeeeeeeeeStep-by-step explanation:
C
6x^2-13X-5=0
(3X+1)(2X-5)
3x-1=0
X=1/3. 2x-5=0. X= 5/2
The equation computed shows that the numbers will be 9, 11 and 13.
<h3>How to illustrate the information?</h3>
Let the numbers be:
First number = x
Second number = x + 2,
Third number = x + 4.
Total of the numbers = 33
The equation will be:
= first + second + third number
x + x + 2 + x + 4 = 33
3x + 6 = 33
Collect like terms
3x = 33 - 6
3x = 27.
Divide both side by 3
3x/3 = 27/3
x = 9
First number = x = 9
Second number = x + 2 = 9 + 2 = 11
Third number = x + 4. = 9 + 4 = 13
The numbers will be 9, 11, and 13.
Learn more about equations on:
brainly.com/question/2972832
#SPJ1
Illustrate the equation to find three consecutive odd integers whose sum is 33.
Answer:
-7/4
Step-by-step explanation:
Recall that slope, m, is defined as the ratio rise to run: rise/run.
Note that if we start at x = -2 (an arbitrary choice), and move 6 units to the right, we end up at x = 4. This is the 'run.' Simultaneously, y starts at 1 and decreases to - 6, a change of -7.
Thus, the slope of the line through these two points is m = rise/run = -7/4
