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lara31 [8.8K]
4 years ago
11

\frac{3}{10} = \frac{x}{x + 2}​10​​3​​=​x+2​​x​​

Mathematics
1 answer:
a_sh-v [17]4 years ago
3 0
7 because the way its set up
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40 x 125% step it out
AlladinOne [14]

Answer:

0.50 or 50%

Step-by-step explanation:

40 x 125 = X

1.25 as a decimal or 125%

40 x 1.25 = 0.50

0.50 --->50%

40 x 125% = 50%

3 0
2 years ago
1. Regina. Phil and Joseph each wrote expressions to represent their hourly
aleksandrvk [35]

Answer:

15

Step-by-step explanation:

Regina: 6.5h

Phil: 3(2.5h+5)

When you plug in the number of hours, you get the weekly pay.  In order to get the same weekly pay, set the equations equal to each other.

6.5h=3(2.5h+5), This is an equation to find the number of hours it will take for them to get equal pay. Now, simplify.

6.5h=7.5h+15

-h=15

h=-15, -15 hours is your answer. You can't work negative hours though which means that Regina and Phil will never be able to make the same amount.

Phil has a higher rate and starting value, this means that Regina will never make the same amount working the same hours.

6 0
3 years ago
Need help what’s 7-11??
nydimaria [60]

Answer:

umm the answer to 7-11 is 69

Step-by-step explanation:

7. Always

8. sometimes

9. never

10. never

11. always

6 0
3 years ago
-3-[(6+3)+(-5-18)]<img src="https://tex.z-dn.net/?f=-3-%5B%286%2B3%29%2B%28-5-18%29%5D" id="TexFormula1" title="-3-[(6+3)+(-5-18
dolphi86 [110]

Answer:

11

Step-by-step explanation:

3 0
2 years ago
How would you solve this problem?
klio [65]

Answer:

a) 6x²/2x³-4

b)  2ln (2x^3-4)+ C

Step-by-step explanation:

a) Given the ln(2x³-4). We will use the chain rule in differentiating the function

If y = ln(2x³-4);

u = 2x³-4; du/dx = 3(2)x³⁻¹

du/dx = 6x²

y = ln u; dy/du = 1/u

According to chain rule, dy/dx = dy/dy*du/dx

dy/dx = 1/u * 6x²

dy/dx = 1/2x³-4 * 6x²

dy/dx = 6x²/2x³-4

Hence, the derivative of the given function is 6x²/2x³-4

b) Given an integral function \int\limits {\frac{12x^2}{2x^3-4} } \, dx, the integral problem can be solved using integration by substitution method as shown below;

From the question, let y = 2x³-4... 1, dy/dx = 6x²

dx = dy/6x² ... 2

Substituting equation 1 and 2 into the question given;

\int\limits {\frac{12x^2}{y} } \,\frac{dy}{6x^2} \\\\= \int\limits {\frac{2dy}{y} } \\\\= 2 \int\limits {\frac{dy}{y} }\\\\= 2lny + C\\substituting\ y = 2x^3-4\ into\ the \ resulting\ function\\\\= 2ln (2x^3-4)+ C

3 0
4 years ago
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