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dlinn [17]
3 years ago
9

The sum of two consecutive intergers is -49.

Mathematics
1 answer:
ZanzabumX [31]3 years ago
6 0

sum is addition

-49/2 = -24.5

so -24 + -25 = -49

 answer is -24 and -25

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plz help me The temperature at noon was 22°. From 6 AM until noon, the temperature changed by an average of 5° per hour. What WA
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Answer:

-8° OR 52°

Step-by-step explanation:

Remember 22.

Now, you'll need to take 12 PM and see how many hours it is from 6 AM to 12 PM noon: 6-7, 7-8, 8-9, 9-10, 10-11, 11-12. We have 6 hours from 6 AM to 12 PM.

The problem gives us the average number of degrees it changed: 5. Since it doesn't specify HOW it changed, there are 2 answers.

In order to find the number of degrees it changed, we have to take the hours times the amount given, or in this case, 6 x 5 which equals 30.

Now that we know the fluxation number, we can either add or subtract 30 from the degrees given at noon.

So, 22 - 30 = <em>-8</em> AND 22 + 30 = <em>50</em>.

I hope that helps! :)

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3 years ago
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8 0
3 years ago
A rectangular shaped garden has an area of 80 square feet. The length is 5 less than twice the width. What are the dimensions of
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Answer:

Width=28 1/3 Length=51 2/3

Step-by-step explanation:

1. Create an equation

x+(2x-5)=80

2. Solve

x+(2x-5)=80

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3x-5+5=80+5

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x=28 1/3

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85/3x2=170/3

56 2/3-5

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2 years ago
A pie can be cut into more than seven pieces by making four diameter cuts.
n200080 [17]
I'm pretty sure it's true
7 0
3 years ago
Read 2 more answers
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

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A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

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I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

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∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
Read 2 more answers
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