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frez [133]
3 years ago
9

An elevator (mass 4850 kg) is to be designed so that the maximum acceleration is 0.0680g. What are the maximum and minimum force

s the motor should exert on the supporting cable?
Physics
1 answer:
pychu [463]3 years ago
7 0
Where T is the tension in the cable, m is the mass of the elevator, and a is the acceleration; remember that the accel can be either up or down
max tension is needed to accelerate the elevator up:
T - 4850g=4850(0.068g)
T=4850g(1+0.068)=50762N
min tension:
T-4850g=-4850(0.068)
T=4850g(1-0.068)
T=44,298N
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