ribosomes
an animal cell with a nucleus
animal
Explanation:
The height of the rise of liquid with capillary tube is given by the formula as follows :
Where
r is radius
It is clear that the height of the rise of liquid is inversely proportional to the radius of the capillary tube.
If the radius of the capillary tube is doubled, it means the height of rise of liquid with capillary tube become half.
Answer:
29.0 g
Explanation:
The mass of the piece of gold is given by:
m = dV
where
m is the mass
d is the density
V is the volume of the piece of gold
The density of gold is
d = 19.3 g/cm^3
while the volume of the sample is equal to the volume of displaced water, so
V = 64.5 mL - 63.0 mL = 1.5 mL
And since
1 mL = 1 cm^3
the volume is
V = 1.5 cm^3
So the mass of the piece of gold is:
m = (19.3 g/cm^3)(1.5 cm^3)=29.0 g
The gravitational force applies depends on the mass of both of the objects.
The initial temperature of the metal bolt is 80.8 °C
We'll begin by calculating the heat absorbed by the water.
- Mass of water (M) = 0.15 Kg
- Initial temperature (T₁) = 21 °C
- Final temperature (T₂) = 25 °C
- Change in temperature (ΔT) = T₂ – T₁ = 25 – 21 = 4 °C
- Specific heat capacity of water (C) = 4184 J/KgºC
Q = MCΔT
Q = 0.15 × 4184 × 4
Q = 2510.4 J
Finally, we shall determine the initial temperature of the metal bolt.
- Heat absorbed by water = 2510.4 J
- Heat released by metal (Q) = –2510.4 J
- Mass of metal (M) = 0.050 Kg
- Final temperature (T₂) = 25 °C
- Specific heat capacity of metal (C) = 899 J/Kg°C
- Initial temperature (T₁) =?
Q = MC(T₂ – T₁)
–2510.4 = 0.050 × 899 (25 – T₁)
–2510.4 = 44.95 (25 – T₁)
Clear bracket
–2510.4 = 1123.75 – 44.95T₁
Collect like terms
–2510.4 – 1123.75 = –44.95T₁
–3634.15 = –44.95T₁
Divide both side by –44.95
T₁ = –3634.15 / –44.95
T₁ = 80.8 °C
Thus, the initial temperature of the metal is 80.8 °C.
Learn more about heat tranfer:
brainly.com/question/26034272
