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Harman [31]
3 years ago
8

A small particle starts from rest from the origin of an xy-coordinate system and travels in the xy-plane. Its acceleration in th

e x-direction is 2.0 m/s2 , and its acceleration in the y-direction is 1.0 m/s2 . What is the x-coordinate of the particle when its y-coordinate is 12 m?
Physics
1 answer:
CaHeK987 [17]3 years ago
5 0

Answer:

The x-coordinate of the particle is 24 m.

Explanation:

In order to obtain the x-coordinate of the particle, you have to apply the equations for Two Dimension Motion

Xf=Xo+Voxt+0.5axt²(I)

Yf=Yo+Voyt+0.5ayt² (II)

Where Xo, Yo are the initial positions, Xf and Yf are the final positions, Vox and Voy are the initial velocities, ax and ay are the accerelations in x and y directions, t is the time.

The particle starts from rest from the origin, therefore:

Vox=Voy=0

Xo=Yo=0

Replacing Yf=12, Yo=0 and Voy=0 in (I) and solving for t:

12=0+(0)t+ 0.5(1.0)t²

12=0.5t²

Dividing by 0.5 and extracting thr squareroot both sides:

t=√12/0.5

t=√24 = 2√6

Replacing t=2√6, ax=2.0,Xo=0 and Vox=0 in (I) to obain the x-coordinate:

Xf=0+0t+0.5(2.0)(2√6)²

Xf= 24 m

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Answer:

0.0133 A

Explanation:

The time at which B=1.33 T is given by  

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Using Faraday's Law, we have  

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Area A = pi * r² = 3.141 *(0.025 *0.025) = 0.00196 m²

emf = - A*(3*0.38)*t^2  

thus, the emf at t=1.52 s is  

emf = - 0.00196*(3*0.38)*(1.52)^2 = -0.0052 V  

if the resistance is 0.390 ohms, then the current is given by  

I = V/R = 0.0052/0.390 = 0.0133 A

3 0
3 years ago
Question 4 A car of mass 820 kg has a maximum power or 30 kW and moves against a constant resistance of motion to 910 N. Calcula
Naddika [18.5K]

Explanation:

power = force × velocity

velocity=power/force

=(30×1000)/910

=32.97m/s

7 0
3 years ago
Which statement bet explains the relationship between the electric force between two charged objects and the distance between th
Nataliya [291]
Coulomb's Law: Force = k x q1x q2 divided distance square
where k=9x10^9 , q1 and q2 are the charge
So if you distance is halved, your force is stronger by 4 times
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4 0
3 years ago
A large man sits on a four-legged chair with his feet off the floor. The combined mass of the man and chair is 95.0 kg. If the c
Leto [7]

Answer:

Pressure, P=29.6\times 10^5\ Pa

Explanation:

It is given that,

Combined mass of the man and the chair, m = 95 kg

Radius of the leg of chair, r = 0.5 cm = 0.005 m

A large man sits on a four-legged chair with his feet off the floor. The force acting per unit area is called the pressure exerted.

P=\dfrac{F}{A}

P=\dfrac{mg}{A}

Area of 4 legs, A = 4 A

P=\dfrac{mg}{4\pi r^2}

P=\dfrac{95\times 9.8}{4\pi (0.005)^2}

P=29.6\times 10^5\ Pa

So, the pressure each leg exert on the floor is 29.6\times 10^5\ Pa. Hence, this is the required solution.

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3 years ago
While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 6.63 m/s. The stone s
gogolik [260]

Answer:

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Explanation:

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=2.19s(to 3s.f.)

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9.81=v-6.63/2.19

v-6.63=21.5

v=28.1m/s

3 0
3 years ago
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