<span>Let's convert the speed to m/s:
speed = (55 mph) (1609.3 m / mile) (1 hour / 3600 seconds)
speed = 24.59 m/s
Let's convert the mass to kilograms:
mass = (2135 lb) (0.45359 kg / lb)
mass = 968.4 kg
We can find the kinetic energy KE:
KE = (1/2) m v^2
KE = (1/2) (968.4 kg) (24.59 m/s)^2
KE = 292780 joules
The kinetic energy of the automobile is 292780 joules.</span>
Power = Iω (constant) as they are connected together, since effort axle has large radius than resistance axle, so moment of inertia of effort axle is also more as compared to resistance axle, so angular speed of effort axle is less than the resistance axle. So answer is B. resistance axle will have more angular speed as its moment of inertia is less for the same power.
Answer:
Total distance traveled = 9 m
Explanation:
Given:
Distance travel towards north = 3 meter
Distance travel towards south = 6 meter
Find:
Total distance traveled
Computation:
Total distance traveled = Sum of total distance
Total distance traveled = Distance travel towards north + Distance travel towards south
Total distance traveled = 3 m + 6 m
Total distance traveled = 9 m
Answer:
10.55111 m/s²
Explanation:
M = Mass of Saturn = ![95\times 5.972\times 10^{24}\ kg](https://tex.z-dn.net/?f=95%5Ctimes%205.972%5Ctimes%2010%5E%7B24%7D%5C%20kg)
r = Radius of Saturn = ![9.4\times 6.371\times 10^6\ m](https://tex.z-dn.net/?f=9.4%5Ctimes%206.371%5Ctimes%2010%5E6%5C%20m)
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
Acceleration due to gravity is given by
![g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 95\times 5.972\times 10^{24}}{(9.4\times 6.371\times 10^6)^2}\\\Rightarrow g=10.55111\ m/s^2](https://tex.z-dn.net/?f=g%3D%5Cdfrac%7BGM%7D%7Br%5E2%7D%5C%5C%5CRightarrow%20g%3D%5Cdfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%2095%5Ctimes%205.972%5Ctimes%2010%5E%7B24%7D%7D%7B%289.4%5Ctimes%206.371%5Ctimes%2010%5E6%29%5E2%7D%5C%5C%5CRightarrow%20g%3D10.55111%5C%20m%2Fs%5E2)
The acceleration due to gravity on Saturn is 10.55111 m/s²
Answer:
Its final velocity and how much time it takes to reach the water
Explanation:
The motion of the stone is a uniformly accelerated motion, so we can use the following suvat equation to determine its final velocity:
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
where
v is the final velocity
u = 0 is the initial velocity
is the acceleration of gravity
s = 52 m is the distance covered during the fall
Solving for v,
![v=\sqrt{u^2+2as}=\sqrt{0^2+2(9.8)(52)}=31.9 m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bu%5E2%2B2as%7D%3D%5Csqrt%7B0%5E2%2B2%289.8%29%2852%29%7D%3D31.9%20m%2Fs)
We can also find how much time it takes to reach the water, using the equation
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
where
v = 31.9 m/s is the final velocity
u = 0 is the initial velocity
t is the time
And solving for t,
![t=\frac{v-u}{a}=\frac{31.9-0}{9.8}=3.26 s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bv-u%7D%7Ba%7D%3D%5Cfrac%7B31.9-0%7D%7B9.8%7D%3D3.26%20s)