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3 years ago

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Hey there! I need help with this question, it's about electromagnets. No absurd answers, please. I will be flagging them. Thanks

!

2 answers:

lozanna [386]3 years ago

3 0

Answer: D Moreecethadev get's 5 stars, Thanks.

Explanation:

Answer is D.

VLD [36.1K]3 years ago

3 0

Answer: I think it’s C. because it definitely needs more wire but it also needs a higher voltage to pick up more, so I don’t know but I think C.

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Please guys help me i will help u too

matrenka [14]

Answer:

calculate the cars acceleration usingv=u+at

Explanation:

m/s. After 5 s the car reaches the bottome of the hill. Its speed at the bottom of the ... accelerating left a rownie. 10. A cart slows down while moving away from the ... does it need to accelerate to a velocity of 20 m/s

3 0

3 years ago

Read 2 more answers

A 1 490-kg automobile has a wheel base (the distance between the axles) of 3.10 m. The automobile's center of mass is on the cen

Kobotan [32]

Answer:

Force on each front wheel = 4711 N

Force on each back wheel = 2591 N

Explanation:

Weight of car = 1490 Kg

Distance of COG from front axle= 1.1 m

Distance of COG from back axle = 3.1 - 1.1 = 2 m

Vertical forces are balanced ,

So, R1 + R2 = mg

R1 + R2 = 1490× 9.8

Thus; R1 + R2 = 14602 - - - eq1

Where

R1 is force on front wheel

R2 is force on back wheel

Now, we know that;

Angular momentum about centre of gravity is zero.

Therefore,

R1 × 1.1 = R2 × 2

R1 = (2/1.1)R2

Put this into equation1, to get;

(2/1.1)R2 + R2 = 14602

R2(2.818) = 14602

R2 = 14602/2.818

R2 = 5182 N and R1 = (2/1.1)5182 = 9422 N

Hence, force on each back wheel = R2/2 = 5182/2 = 2591 N

Force on each front wheel = R1/2 = 9422/2 = 4711 N

4 0

3 years ago

Three resistors connected in series have potential differences across them labeled /\V1 , /\V2 , and /\V3. What expresses the po

Brrunno [24]

Answer:

$\Delta V=\Delta V_1+\Delta V_2+\Delta V_3$

Explanation:

We are given that three resistors R1, R2 and R3 are connected in series.

Let

Potential difference across $R_1=\Delta V_1$

Potential difference across $R_2=\Delta V_2$

Potential difference across $R_3=\Delta V_3$

We know that in series combination

Potential difference , $V=V_1+V_2+V_3$

Using the formula

$\Delta V=\Delta V_1+\Delta V_2+\Delta V_3$

Hence, this is required expression for potential difference.

3 0

3 years ago

Brianna pushes a 20 kg box with a force of 50N to achieve an acceleration of 2.5 m/s/s. In order to push a 30 kg box at the same

Elanso [62]

Answer:

She applies 75N of force

Explanation:

F=ma

50=20(2.5)

F=30(2.5)

F=75 N

5 0

3 years ago

point A is at the bottom of a rough plane which is inclined at angle tita to the horizontal . A body of mass M is projected from

ziro4ka [17]

<h2>The work done , when body moves along the plane </h2>

Explanation:

A body is projected from bottom of the inclined plane . When body is going up the plane .

The downward force = m g sinθ is developed due to its weight

As body is moving upwards , the force of friction will act downwards

The force of friction = μ R

here μ is the coefficient of friction ans R is the normal reaction

Thus force of friction f = μ mg cosθ

Let the acceleration upwards is a

The upward force required = m a

Thus m a = mg sinθ + μ mg cosθ

or acceleration a = g ( sinθ + μ cosθ )

The work done in moving upwards W = F S

Thus W = mg ( sinθ + μ cosθ ) S

here S is the displacement on the plane

When body moves down , the force of friction acts upwards

Thus m a = m g ( sinθ - μ cosθ )

The work done W = m g ( sinθ - μ cosθ ) S

As the body is projected with velocity u

which can be calculated by the relation v² - u² = - 2 a X

Here v = 0 at the highest point

Thus u = $\sqrt{2ax}$

here a = g ( sinθ + μ cosθ )

Similarly , when it moves down , the initial velocity u = 0

Thus v² - 0 = 2 a x

or v = $\sqrt{2ax}$

here a = g ( sinθ - μ cosθ )

3 0

3 years ago