Ask question

Ask question

All categories

2 years ago

8

Hey there! I need help with this question, it's about electromagnets. No absurd answers, please. I will be flagging them. Thanks

!

2 answers:

lozanna [386]2 years ago

3 0

Answer: D Moreecethadev get's 5 stars, Thanks.

Explanation:

Answer is D.

VLD [36.1K]2 years ago

3 0

Answer: I think it’s C. because it definitely needs more wire but it also needs a higher voltage to pick up more, so I don’t know but I think C.

You might be interested in

A child has a toy car on a horizontal platform. The car starts from rest and reaches a maximum speed in 4 s. If the mass of the

dmitriy555 [2]

Answer:

a=4m/s²

Explanation:

F=ma

0.4=0.1a

7 0

3 years ago

Read 2 more answers

A sailfish swims 120 km/hr. How far will it travel in 8.0 minutes?

Rasek [7]

Answer:

16km

Explanation:

First change the minutes into hours then multiply by the distance.

(8÷60)×120=16km

5 0

3 years ago

The electron dot diagram shows the arrangement of dots without identifying the element.

olasank [31]

<em>Answer: </em>tellurium (Te)

<em>atomic number = 52 ,</em>

<em>Number of energy levels = 5;</em>

First energy level = 2

Second energy level = 8

Third energy level = 18

Fourth energy level = 18

Fifth energy level = 6

<em>In this electron configuration, 0uter most electrons are 6.</em>

5 0

2 years ago

Read 2 more answers

Predict the precipitate when the double replacement reaction occurs:<br> Ca(NO3)2(aq) + Na2CO3(aq) →

taurus [48]

Ca(NO3)2(aq) + Na2CO3(aq) → 2NaNO3 + CaCO3⬇. NaNO3 is solution so CaCO3 is the precipitate formed.

8 0

3 years ago

Read 2 more answers

An unstable atomic nucleus has a mass of 17.010-27kg, and starts out at rest. When it decays, it the original nucleus disintegra

slega [8]

Answer:

Part a)

$v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s$

Part b)

$E = 4.4 \times 10^{-13} J$

Explanation:

As per momentum conservation we know that there is no external force on this system so initial and final momentum must be same

So we will have

$m_1v_1 + m_2v_2 + m_3v_3 = 0$

$(5 \times 10^{-27})(6 \times 10^6\hat j) + (8.4 \times 10^{-27})(4 \times 10^6\hat i) + (3.6 \times 10^{-27}) v = 0$

$(30\hat j + 33.6\hat i)\times 10^6 + 3.6 v = 0$

$v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s$

Part b)

By equation of kinetic energy we have

$E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 + \frac{1}{2}m_3v_3^2$

$E = \frac{1}{2}(5 \times 10^{-27})(6\times 10^6)^2 + \frac{1}{2}(8.4 \times 10^{-27})(4 \times 10^6)^2 + \frac{1}{2}(3.6 \times 10^{-27})(8.33^2 + 9.33^2) \times 10^{12}$

$E = 9\times 10^{-14} + 6.72 \times 10^{-14} + 2.82\times 10^{-13}$

$E = 4.4 \times 10^{-13} J$

8 0

3 years ago