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larisa [96]
3 years ago
8

Hey there! I need help with this question, it's about electromagnets. No absurd answers, please. I will be flagging them. Thanks

!

Physics
2 answers:
lozanna [386]3 years ago
3 0

Answer: D Moreecethadev get's 5 stars, Thanks.

Explanation:

Answer is D.

VLD [36.1K]3 years ago
3 0

Answer: I think it’s C. because it definitely needs more wire but it also needs a higher voltage to pick up more, so I don’t know but I think C.

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an egg (0.05 kg) hits the ground at a speed of 10 m/s and cracks . what was the momentum of the egg when it hit?
Anastaziya [24]
The momentum should be .5 because you multiply the mass and velocity to get momentum
6 0
3 years ago
A 4.5 g coin sliding to the right at 23.8 cm/s makes an elastic head-on collision with a 13.5 g coin that is initially at rest.
Airida [17]

Answer:

a) v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} ), b) \Delta K = 9.559\times 10^{-5}\,J

Explanation:

a) The final velocity of the 13.5 g coin is found by the Principle of Momentum Conservation:

(4.5\times 10^{-3}\,kg)\cdot (23.8\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot (0\,\frac{m}{s} ) = (4.5\times 10^{-3}\,kg)\cdot (-11.9\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot v

The final velocity is:

v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} )

b) The change in the kinetic energy of the 13.5 g coin is:

\Delta K = \frac{1}{2}\cdot (13.5\times 10^{-3}\,kg)\cdot \left[(11.9\times 10^{-2}\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}\right]

\Delta K = 9.559\times 10^{-5}\,J

4 0
3 years ago
Read 2 more answers
What is the definition of the coefficient of kinetic friction?
Nookie1986 [14]
The coefficient of kinetic friction<span> is the force between two objects when one object is moving, or if two objects are moving against each other</span>
4 0
4 years ago
I need help by today
babymother [125]

The answer is B. Well it's the best answer.

6 0
4 years ago
What is the spring constant (in n/m) of a spring that stores 100 J of elastic potential energy when it is stretched 5 m?
kogti [31]

Answer:

8N/m

Explanation:

The elastic potential energy stored can be calculated using the equation:

elastic potential energy = 0.5 × spring constant × (extension)2

assuming it is not stretched beyond the limit of proportionality.

Then calculate using the values in the question:

100J = 0.5 × spring constant × 5²

200J = spring constant × 25

spring constant = 200J ÷ 25m²

spring constant = 8J/m²

spring constant = 8N/m

8 0
4 years ago
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