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Iteru [2.4K]
3 years ago
11

During which two moon phases would the amount of light reflected from the moon appear to be equal from Earth? Why does this occu

r at different times in a month? (AKS6a, DOK 3)
A.
The light reflected appears the same during the new moon and full moon phases because the sun, moon and Earth are aligned.

B.
The light reflected appears the same during the new moon and first quarter moon phases because the sun, moon and Earth are at the same angles.

C.
The light reflected appears the same during the full moon and third quarter moon phases because the sun, moon and Earth are at the same angles.

D.
The light reflected during the first quarter and third quarter moon phases appears equal because the sun, moon and Earth are at right angles.
Physics
1 answer:
shusha [124]3 years ago
6 0

The moon phase shows that D. light reflected during the first quarter and third quarter moon phases appears equal because the sun, moon and Earth are at right angles.

<h3>What is a moon phase?</h3>

It should be noted that the <em>moon</em> phase simply means the portion of the moon that we can see from the Earth.

In this case, the light reflected during the first quarter and third quarter moon phases appears equal because the sun, moon and Earth are at right angles.

Learn more about moon on:

brainly.com/question/398659

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5 0
3 years ago
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Which statement best summarizes Newton's law of action-reaction? *
Tom [10]

Answer:

The correct answer is the third

Force equals mass times acceleration

Explanation:

Newton's second law says that force equals mass times the acceleration of the body

            F = m a

This is the most used way to solve problems

The correct answer is the third

Newton's third law states that forces always work in pairs, by action and reaction

Newton's first law states that an object per macerate with constant speed unless some force modifies this state.

4 0
3 years ago
A slingshot fires a pebble from the top of a building at a speed of 17.5 m/s. The building is 31.5 m tall. Ignoring air resistan
Jlenok [28]

Answer:

The speed with which the pebble strikes the ground is 30.4m/s

Explanation:

Initial velocity (u) = 17.5m/s, height (h) = 31.5m, acceleration due to gravity (g) = 9.8m/s^2

V^2 = u^2 + 2gh = 17.5^2 + 2×9.8×31.5 = 306.25 + 617.4 = 923.65

V^2 = 923.65

V = √923.65 = 30.4m/s

6 0
4 years ago
A sprinter accelerates from rest to 10.0 m/s in 1.35 seconds. What is their<br> acceleration?
ipn [44]

Answer:

0.135

Explanation:

You need to divide

4 0
4 years ago
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Lars is standing near the edge of a 90-meter cliff. He throws a ball upward, but does not catch it, and it falls to the bottom o
Kipish [7]

Answer:

c. 43 m/s

Explanation:

Given the following data;

Displacement, S = 90 meters

Time, t = 5.55 seconds

To find the initial velocity;

We would use the second equation of motion given by the formula;

S = ut + \frac {1}{2}at^{2}

Where;

  • S represents the displacement or height measured in meters.
  • u represents the initial velocity measured in meters per seconds.
  • t represents the time measured in seconds.
  • a represents acceleration measured in meters per seconds square.

We know that acceleration due to gravity is -9.8m/s² because the direction is downward.

Substituting into the equation, we have;

90 = u*5.55  + \frac {1}{2}*(-9.8)*5.55^{2}

90 = u5.55 - 4.9*30.8025

90 = u5.55 - 150.93225

Rearranging the equation, we have;

u5.55 = 90 + 150.93225

u5.55 = 240.93225

u = \frac {240.93225}{5.55}

Initial velocity, u = 43.41 ≈ 41 m/s

4 0
3 years ago
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