What id the volume if a gas if I have 0.215 moles if gas at a temperature of 75 K and a pressure if 182.34KPa?
1 answer:
This problem tests the concept of general gas equation, which is:
PV = nRT
Where,
P = Pressure
V = Volume
n = number of moles
R = General gas constant
T = Temprature
We are to find V, and we have the rest of the values.
P = 183.24 KPa = 183240 Pa
n = 0.215 moles
T = 75 K
R = 8.314 J /(mol.K)
Using the values in the equation, we get:
V = 0.000732 m³
The value of volume is cubic meter. In cubic cm, the value of volume will be:
V = 0.000732 x 1000000 = 732 cm³
PV = nRT
Where,
P = Pressure
V = Volume
n = number of moles
R = General gas constant
T = Temprature
We are to find V, and we have the rest of the values.
P = 183.24 KPa = 183240 Pa
n = 0.215 moles
T = 75 K
R = 8.314 J /(mol.K)
Using the values in the equation, we get:
V = 0.000732 m³
The value of volume is cubic meter. In cubic cm, the value of volume will be:
V = 0.000732 x 1000000 = 732 cm³
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Answer:
Molarity of the solution? 0,262 M.
Concentration of the potassium cation? 0,786 M.
Concentration of the phosphate anion? 0,262 M.
Explanation:
Potassium phosphate (K₃PO₄; 212,27 g/mol) dissolves in water thus:
K₃PO₄ → 3 K⁺ + PO₄³⁻ <em>(1)</em>
Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.
There are 250 mL of solution≡0,25 L
The moles of K₃PO₄ are:
13,9 g of K₃PO₄ × = 0,0655 moles of K₃PO₄
The molarity of the solution is:
= 0,262 M
In (1) you can see that 1 mole of K₃PO₄ produces 3 moles of potassium cation. The moles of potassium cation are:
0,0655 moles×3 = 0,1965 moles
The concentration is:
= 0,786 M
The moles of K₃PO₄ are the same than moles of PO₄³⁻, thus, concentration of phosphate anion is the same than concentration of K₃PO₄. 0,262 M
I hope it helps!