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3 years ago

Which diagram shows a pair of electrons that have opposite spins? 011 1 011 o 11h

Chemistry

1 answer:

Neporo4naja [7]3 years ago

5 0

Answer:

1 one is the right........

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CH,O<br> Needed:<br> Available:<br> Shared:<br> Bonds:

Alona [7]

Answer:

hy do C-C bonds and C-H bonds have high potential energy levels? ... electronegativity so the electrons in the covalent bond are equally shared. Term. Which functional groups are commonly found on a carbohydrate? ... few organisms have the specific enzymes needed to break the bond in the B-form ...

Explanation:

3 0

2 years ago

Plot the data points on the graph below and use the corresponding dot colors: 1st data point - blue, 2nd data point - yellow, 3r

yulyashka [42]

Answer:

The answer is an attached file

Explanation:

I hope it'll be useful to you.

4 0

3 years ago

Read 2 more answers

Making jam and dry ice sublimating and becoming a gas are exapleanof what

Natali [406]

Answer:

Sublimation is a phase transition that occurs when a solid changes into a gas — or, as

Explanation:

3 0

3 years ago

3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh

TiliK225 [7]

Answer:

$n_{C_6H_{10}}=0.03molC_6H_{10}$

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

$n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}$

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

$m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}$

Even thought, the volume could be also computed by using its density:

$V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}$

Best regards.

4 0

2 years ago

Read 2 more answers

What is the density of a 805 g sample of pure silicon with a volume of 2.3 cm3?

MAVERICK [17]

The density of it would be 57. Do the math and apply the formula to it and you would get this answer.

3 0

3 years ago