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fiasKO [112]
3 years ago
8

Harold cut 18 1/2 inches off a rope that was 60 inches long. How is the length of the remaining rope written in decimals?

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:41.5

If you do 60- 18.5 (1/2 = 0.5), you get about 41.5 inches left of the rope.

Step-by-step explanation:

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there are 12 players on the basketball roster. 9 of the players are in the 8th grade. What percent of the team is not in the 8th
alexandr402 [8]
Well there are 12 players and 9 are in 8th grade so the rest is leaving 3 so 3/12 so converted to percentage is 25% hoped this helped
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Find the average range. Round the mean and the average range to the nearest tenth. (Show all your work on scratch paper, then en
NISA [10]
3, 12, 15, 25, 30, 40The range is the difference between the greatest and smallest values:
range = 40 - 3 = 37

Thee average is the sum of elements divided by the number of elements:
average = (<span>3 + 12 + 15 + 25 + 30 + 40</span>)/6
average = 125/6 = 20.83
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Which of the following lists of ordered pairs is a function
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Step-by-step explanation:

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3 years ago
Read 2 more answers
What would x equal in this equation
KATRIN_1 [288]

Answer:

x = 15

Step-by-step explanation:

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Check your work:

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8 0
3 years ago
A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a
tatuchka [14]

Answer:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

df=n-1=15-1=14  

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

\bar X=42.6 represent the average nicotine content

s=3.7 represent the sample standard deviation

n=15 sample size  

\mu_o =40 represent the value to check

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

The statistic for this case would be:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replcing we got:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

The degrees of freedom are:

df=n-1=15-1=14  

The p value would be:

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

6 0
3 years ago
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