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FromTheMoon [43]
3 years ago
13

The cheerleading team is doing a car wash for a fundraiser. They are able to wash an average of 1 1/2 cars each 1/6 hour. What i

s the unit rate for cars they can wash per hour?
Mathematics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

9 cars/hour

Step-by-step explanation:

1.5 cars=1/6 hours

multiply both by 6

9 cars=1 hour

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Find the area of the trapezoid
Sergeeva-Olga [200]

Answer:

44

Step-by-step explanation:

Formula

\frac{1}{2}  \times h \times (sum \: of \: parallel \: sides(b1 + b2))

Your scale is 2cm to 2units therefore the parameters are as follows

h=4

b1=9

b2=13

\frac{1}{2}  \times 4 \times (9 + 13)

\frac{1}{2}  \times 4 \times 22

\frac{1}{2}  \times 88

\frac{88}{2}  \\  = 44

6 0
3 years ago
Find YQ if MQ = 3x-3 and YQ = 2x-6.
Alina [70]

Answer:

• Assume Q is a mid point of line MY

{ \underline{ \sf{ \:  _{l} M \:  \:  \:  \:  \:  \:  \:  \:  _{l} Q \:  \:  \:  \:  \:  \:  \:  \:  _{l}Y}}}

• Then, MQ = YQ

{ \rm{(3x - 3) = (2x - 6)}} \\  \\ { \rm{3x - 2x =  - 6 + 3}} \\  \\ { \boxed{ \rm{ \: x =  - 3 \: }}}

5 0
2 years ago
Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m
ch4aika [34]

Answer:

\ln x+\frac{1}{3}\ln (x^2+1)

Step-by-step explanation:

Consider the given expression is

\ln (x\sqrt[3]{x^2+1})

We need to rewrite the expression as a sum,difference,or multiple of logarithms.

\ln (x(x^2+1)^{\frac{1}{3}})        [\because \sqrt[n]{x}=x^{\frac{1}{n}}]

Using the properties of logarithm we get

\ln x+\ln (x^2+1)^{\frac{1}{3}}         [\because \ln (ab)=\ln a+\ln b]

\ln x+\frac{1}{3}\ln (x^2+1)        [\because \ln (a^b)=b\ln a]

Therefore, the simplified form of the given expression is \ln x+\frac{1}{3}\ln (x^2+1).

6 0
3 years ago
C2d3 has a solubility product constant of 9.14×10−9. what is the molar solubility of c2d3?
UkoKoshka [18]
The correct answer for the question that is being presented above is this one:

We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>

<span>Then set that equation equal to your solubility constant </span>

<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3 
</span>
<span>So the molar solubility is 9.67x10-3</span>
4 0
3 years ago
Evaluate and reduce:
AfilCa [17]

Answer:

-31/8

Please mark me as brainliest

6 0
2 years ago
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