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FromTheMoon [43]

3 years ago

13

The cheerleading team is doing a car wash for a fundraiser. They are able to wash an average of 1 1/2 cars each 1/6 hour. What i

s the unit rate for cars they can wash per hour?

1 answer:

Mrrafil [7]3 years ago

4 0

Answer:

9 cars/hour

Step-by-step explanation:

1.5 cars=1/6 hours

multiply both by 6

9 cars=1 hour

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Find the area of the trapezoid

Sergeeva-Olga [200]

Answer:

44

Step-by-step explanation:

Formula

$\frac{1}{2} \times h \times (sum \: of \: parallel \: sides(b1 + b2))$

Your scale is 2cm to 2units therefore the parameters are as follows

h=4

b1=9

b2=13

$\frac{1}{2} \times 4 \times (9 + 13)$

$\frac{1}{2} \times 4 \times 22$

$\frac{1}{2} \times 88$

$\frac{88}{2} \\ = 44$

6 0

3 years ago

Find YQ if MQ = 3x-3 and YQ = 2x-6.

Alina [70]

Answer:

• Assume Q is a mid point of line MY

${ \underline{ \sf{ \: _{l} M \: \: \: \: \: \: \: \: _{l} Q \: \: \: \: \: \: \: \: _{l}Y}}}$

• Then, MQ = YQ

${ \rm{(3x - 3) = (2x - 6)}} \\ \\ { \rm{3x - 2x = - 6 + 3}} \\ \\ { \boxed{ \rm{ \: x = - 3 \: }}}$

5 0

2 years ago

Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m

ch4aika [34]

Answer:

$\ln x+\frac{1}{3}\ln (x^2+1)$

Step-by-step explanation:

Consider the given expression is

$\ln (x\sqrt[3]{x^2+1})$

We need to rewrite the expression as a sum,difference,or multiple of logarithms.

$\ln (x(x^2+1)^{\frac{1}{3}})$ $[\because \sqrt[n]{x}=x^{\frac{1}{n}}]$

Using the properties of logarithm we get

$\ln x+\ln (x^2+1)^{\frac{1}{3}}$ $[\because \ln (ab)=\ln a+\ln b]$

$\ln x+\frac{1}{3}\ln (x^2+1)$ $[\because \ln (a^b)=b\ln a]$

Therefore, the simplified form of the given expression is $\ln x+\frac{1}{3}\ln (x^2+1)$ .

6 0

3 years ago

C2d3 has a solubility product constant of 9.14×10−9. what is the molar solubility of c2d3?

UkoKoshka [18]

The correct answer for the question that is being presented above is this one:

We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>

<span>Then set that equation equal to your solubility constant </span>

<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3
</span>
<span>So the molar solubility is 9.67x10-3</span>

4 0

3 years ago

Evaluate and reduce:

AfilCa [17]

Answer:

-31/8

Please mark me as brainliest

6 0

2 years ago