Answer:
23 is the answer the J is acute but it has a vary so it is even smaller than 49 so it's like subtracting 26
If the function factors and the bottom term cancels, the discontinuity at the x-value for which the denominator was zero is removable, so the graph has a hole in it. After canceling, it leaves you with x – 7. Therefore x + 3 = 0 (or x = –3) is a removable discontinuity..
Answer: the answer is approximately 41.65428, not rounded (maybe re do all the steps just in case)
Step-by-step explanation:
1. label the space between X and W the unknown.
2. You will be using SOH-CAH-TOA
3. Label the X as the opposite because it is the opposite side of where your degree is located.
4. Label five as adjacent because it’s next to the degree.
5. You will use TOA since you have adjacent and opposite values.
6. Write the equation tan58=x/5, the unknown goes on the top because O is first, the five goes on the bottom because A is last on TOA.
7. After you have the equation time 5 on both sides leaving you out with (5)tan58=x
8. On your calculator time (5)tan58 which will give you x.
Answer:
9.434 units
Step-by-step explanation:
Given data
points (5,4) and (-3,-1)
x1= 5
y1= 4
x2= -3
y2= -1
The expression for the distance between two points is
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((-3-5)²+(-1-4)²)
d=√((-8)²+(-5)²)
d=√64+25
d=√89
d=9.4339
d= 9.434 units
Hence the distance between the points is 9.434 units
