Rational numbers are the numbers that can be written as the fraction of two integers and absolute value is the distance a number is away from 0. If we look at a number line, the absolute value is the distance any number on the number line is away from 0. Distance is always positive, so our absolute value is always 0.
Answer:
n=3
Step-by-step explanation:
Simplifying
8n + 12 + -5n = 21
Reorder the terms:
12 + 8n + -5n = 21
Combine like terms: 8n + -5n = 3n
12 + 3n = 21
Solving
12 + 3n = 21
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '-12' to each side of the equation.
12 + -12 + 3n = 21 + -12
Combine like terms: 12 + -12 = 0
0 + 3n = 21 + -12
3n = 21 + -12
Combine like terms: 21 + -12 = 9
3n = 9
Divide each side by '3'.
n = 3
Simplifying
n = 3
Answer:
The dimension of the sandbox is (2x+1) by (x - 3)
Step-by-step explanation:
It seems the complete question will be:
The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of x.
Step-by-step explanation:
From the question, the given expression is 2X^2-5x-3. This can be rewritten as
![2x^{2} -5x-3](https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-5x-3)
If the area of the sandbox in park is represented by this expression, then the dimensions of the sandbox will be the product of the factors. To determine the factors, we will factorize the given quadratic expression.
Factorizing the expression
, we get
![2x^{2} -6x+x-3](https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-6x%2Bx-3)
![2x(x-3)+1(x-3)](https://tex.z-dn.net/?f=2x%28x-3%29%2B1%28x-3%29)
![(2x+1)(x-3)](https://tex.z-dn.net/?f=%282x%2B1%29%28x-3%29)
Hence, the dimension of the sandbox is (2x+1) by (x - 3)
37 is prime so it is reduced to its lowest form.
33/44 simplifies to 3/4