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frosja888 [35]
3 years ago
9

Find the limit. lim (x-5)/((x^2)-25) x-> 5+

Mathematics
2 answers:
REY [17]3 years ago
7 0
\lim_{x \to 5}  \frac{x-5}{ x^{2} -25} =( \frac{0}{0} ) = \\  =\lim_{x \to 5}  \frac{x-5}{(x-5)(x+5)}= \\  =\lim_{x \to 5}  \frac{1}{x+5}= \\ = \frac{1}{5+5}= \frac{1}{10} = 0.1
Mashcka [7]3 years ago
5 0
(5x-5 = 23- -56 hope this didnt help
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