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4 years ago

What does a mole of iron weigh

Chemistry

1 answer:

r-ruslan [8.4K]4 years ago

3 0

As the atomic mass of iron is 55.847u

We say that it is the mass of one mole of iron.

By formula it can be find by

No.of mole=mass in g/molar mass

Mass in gram = no.of mole x molar mass

No.of mole =1

Molar mass = 55.847g

Mass in gram = 1x55.847

= 55.847g of Fe

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A 11.79 g sample of Mo2O3(s) is converted completely to another molybdenum oxide by adding oxygen. The new oxide has a mass of 1

Elis [28]

Answer:

MoO₃

Explanation:

To solve this question we must find the moles of molybdenum in Mo2O3. The moles of Mo remain constant in the new oxide. With the differences in masses we can find the mass of oxygen and its moles obtaining the empirical formula as follows:

<em>Moles Mo2O3 -Molar mass: 239,878g/mol-</em>

11.79g * (1mol / 239.878g) = 0.04915 moles Mo2O3 * (2mol Mo / 1mol Mo2O3) = 0.09830 moles Mo

<em>Mass Mo in the oxides:</em>

0.09830 moles Mo * (95.95g/mol) = 9.432g Mo

<em>Mass oxygen in the new oxide:</em>

14.151g - 9.432g = 4.719g oxygen

<em>Moles Oxygen:</em>

4.719g oxygen * (1mol/16g) = 0.2949 moles O

The ratio of moles of O/Mo:

0.2949molO / 0.09830mol Mo = 3

That means there are 3 moles of oxygen per mole of Molybdenum and the empirical formula is:

3 0

3 years ago

When 5.0 moles of butane react completely?

Korolek [52]

Moles of Carbondioxide-CO₂ produced = 20 moles

<h3>Further explanation</h3>

The combustion of hydrocarbons with excess oxygen will produce carbon dioxide and water(CO₂+H₂O), whereas if there is not much oxygen, carbon monoxide and water(CO+H₂O) will be obtained.

The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds

Reaction (combustion of butane) :

Butane reacts completely, then Butane is the limiting reactant and oxygen as the excess reactant, so the moles of Carbon dioxide are based on the butane moles as the limiting reactant.

moles of butane - C₄H₁₀ = 5 moles

From the reaction, the mol ratio of C₄H₁₀ and CO₂ : 2 : 8, so mol CO₂ :

$\tt \dfrac{8}{2}\times 5~moles=20~moles$

7 0

3 years ago

In the diagram, what is happening to the ENERGY during Segment C? Phase Change Diagram_Water Question 16 options: The kinetic en

Leviafan [203]

There was an increase in kinetic energy during the segment C and in other segments

Recall: That temperature is a measure of the average kinetic energy, so increasing temperature all cause increasing kinetic energy and vice versa.

However too, the heat energy which is added during the phase change is usually used to overcome forces in order to hold the molecules together.

<h3>What is kinetic energy?</h3>

Kinetic energy is the type of energy an object or a body posesss due to it motion

The body usually maintains it's kinetic energy unless the speed changes

<h3>What it potential energy?</h3>

Potential energy is a type of energy an object or a body had due to its relative position.

Learn more about kinetic and potential energy:

brainly.com/question/13584911f

4 0

3 years ago

Name the parts of an electromagnet

Oxana [17]

Answer:

The iron core, copper wire, and an electricity source.

Explanation: Me

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3 years ago

A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.

solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

$Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J$

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

$E = \frac{h \times c }{\lambda }$

where,

h: Planck's constant

c: speed of light

$E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J$

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

$\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J$

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

$Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%$

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

8 0

3 years ago