1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
seraphim [82]
2 years ago
15

You have 3 L of a 5M solution of calcium chloride. How many L would you be able to make of a 0.5M solution?

Chemistry
1 answer:
san4es73 [151]2 years ago
3 0

Answer:

30.0 L.

Explanation:

  • To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.

<em>(MV)before dilution = (MV)after dilution</em>

M before dilution = 5.0 M, V before dilution = 3.0 L.

M after dilution = 0.5 M, V after dilution = ??? L.

∵ (MV)before dilution = (MV)after dilution

∴ (5.0 M)(3.0 L) = (0.5 M)(V after dilution)

<em>∴ V after dilution = (5.0 M)(3.0 L)/(0.5 M) = 30.0 L.</em>

You might be interested in
What happens to the density of the air in the balloon as it is heated?
dexar [7]
Hope it helped you.

7 0
2 years ago
Calculate the pH of the resulting solution if 26.0 mL of 0.260 M HCl(aq) is added to:
enyata [817]
So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
7 0
3 years ago
Zn + 2HCl -----&gt; ZnCl2 + H2 <br> what mass of ZnCl2 will be produced if 25g of Hcl react
labwork [276]
What? It would be nice if you show pic
5 0
2 years ago
A volume of saline solution had a mass of 61.4 g at 4°C. An equal volume of water at the same
Maurinko [17]
Multiple by 2 because it was give u right answer
5 0
2 years ago
The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse
Umnica [9.8K]
Answer : 121.5 <span>μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.

We can use this formula;

</span>\frac{N}{ N_{0} } =  e^{-( \frac{0.693 X  T_{2} }{T_{1}})

3.8 / N_{0} = e^ ((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5  </span>μci
5 0
2 years ago
Read 2 more answers
Other questions:
  • Name the product(s) of the complete combustion of any hydrocarbon.
    14·1 answer
  • An element has atomic number 10 and an atomic mass of 20. How many neutrons are in the atom of this element? A. 10 B. 20 C. 30 D
    10·1 answer
  • Balanced chemical equation for the decomposition of solid sodium sulfide in aqueous solution.
    15·1 answer
  • Helpppppppppppppppppppppppppppppppppppppppppppp
    12·1 answer
  • Explain the term contact force and give examples​
    11·1 answer
  • Mr. Thorton, the science teacher, was explaining the difference between kinetic and potential energy. He compared the difference
    5·2 answers
  • Tulle
    6·1 answer
  • How is aluminum used in a lithium ion type of battery?
    14·1 answer
  • Consider the model of the nitrogen atom.
    9·2 answers
  • PLEASE HELP QUICK I NEED 14-16 (JUST 6 PROBLEMS) ANSWERED AND FULL WORK SHOWN FOR FACTOR LABEL METHOD ITS 100 POINTS AND I WILL
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!