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seraphim [82]
3 years ago
15

You have 3 L of a 5M solution of calcium chloride. How many L would you be able to make of a 0.5M solution?

Chemistry
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

30.0 L.

Explanation:

  • To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.

<em>(MV)before dilution = (MV)after dilution</em>

M before dilution = 5.0 M, V before dilution = 3.0 L.

M after dilution = 0.5 M, V after dilution = ??? L.

∵ (MV)before dilution = (MV)after dilution

∴ (5.0 M)(3.0 L) = (0.5 M)(V after dilution)

<em>∴ V after dilution = (5.0 M)(3.0 L)/(0.5 M) = 30.0 L.</em>

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50 J of work was done on a system, as a result of which 29 J of heat energy was removed from it. How would this affect the inter
cricket20 [7]
  • Work done=50J
  • Heat removed=29J

Now

\\ \sf\longmapsto \Delta E=50-29

\\ \sf\longmapsto \Delta E=21J

  • Hence the internal energy would increase by 21J

Option B is correct

3 0
3 years ago
Read 2 more answers
What volume (in liters) of a 1.772 M BaCl2 solution is needed to obtain 123 g of BaCl2?
kap26 [50]

Answer:

Volume required = 0.327 L

Explanation:

Given data:

Volume in L = ?

Molarity of solution = 1.772 M

Mass of BaCl₂ = 123 g

Solution:

First of all we will calculate the number of moles of BaCl₂,

Number of moles = mass/molar mass

Number of moles = 123 g/ 208.23 g/mol

Number of moles = 0.58 mol

Now, given problem will solve by using molarity formula.

Molarity = number of moles / volume in L

1.772 M = 0.58 mol / Volume in L

Volume in L = 0.58 mol  / 1.772 M

Volume in L = 0.327 L

8 0
2 years ago
Calculate the pH of a solution that is 0.205M benzoic acid and 0.230M sodium benzoate, a salt whose anion is the conjugate base
pickupchik [31]

Answer:

pH = 4.25

Explanation:

A solution composed of a weak acid and its conjugate base is a <em>buffer solution</em>. To calculate the pH of a buffer solution we use the Henderson-Hasselbach equation:

pH = pKa + log ([conjugate base]/[weak acid]

In this case, we have the following data:

[conjugate base] = [sodium benzoate] = 0.230 M

[weak acid] = [benzoic acid] = 0.205 M

The pKa of benzoic acid is 4.2. So, we introduce the data in the equation:

pH = 4.2 + log (0.230 M/0.205 M) = 4.2 + 0.050 = 4.25

4 0
3 years ago
If you dissolve 3.5 moles of cacl2 in solution how many moles of ca2+ ions and cl- ions will there be in the solution
Wittaler [7]
Balanced chemical reaction (dissociation) : CaCl₂(aq)  → Ca²⁺(aq) + 2Cl⁻(aq).
n(CaCl₂) = 3,5 mol.
From chemical reaction: n(CaCl₂) : n(Ca²⁺) = 1 : 1.
n(Ca²⁺) = 3,5 mol.
From chemical reaction: n(CaCl₂) : n(Cl⁻) = 1 : 2.
n(Cl⁻) = 2 · 3,5 mol.
n(Cl⁻) =  7 mol.
Calcium chloride is salt that completely dissociate in water on calcium cations and chlorine anions.
8 0
3 years ago
Why is it so important in an ideal simple experiment to change only one variable from trial to trial?
RideAnS [48]
Because if you change two things then you do not know which one has affected or altered the dependent variable.  if you only change one then you know what exactly changed and why
3 0
3 years ago
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