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seraphim [82]
3 years ago
15

You have 3 L of a 5M solution of calcium chloride. How many L would you be able to make of a 0.5M solution?

Chemistry
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

30.0 L.

Explanation:

  • To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.

<em>(MV)before dilution = (MV)after dilution</em>

M before dilution = 5.0 M, V before dilution = 3.0 L.

M after dilution = 0.5 M, V after dilution = ??? L.

∵ (MV)before dilution = (MV)after dilution

∴ (5.0 M)(3.0 L) = (0.5 M)(V after dilution)

<em>∴ V after dilution = (5.0 M)(3.0 L)/(0.5 M) = 30.0 L.</em>

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Explanation:

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Given that you started with 28.5 g of K3PO4, how many grams of KNO3 can be<br> produced?
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<h3>Further explanation</h3>

Given

28.5 g of K₃PO₄

Required

Mass of KNO₃

Solution

Reaction(Balanced equation) :

2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃

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