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GalinKa [24]
3 years ago
12

What are the genotypic and phenotypic ratios

Chemistry
2 answers:
inessss [21]3 years ago
8 0

- Genotype is the genetic make-up of an organism that describes the nature of each trait. (the letters we often write for a certain trait)

- Phenotype is the morphology of a living organism .(the trait you usually observe while looking/tracking the organism)

Example:

- In the flower of a pea plant there are a pink color(RR) or (Rr) and a white color(rr).

- When crossing two hybrid ( with two different letters) pink colors,

P  :     Rr        ×      Rr  

G :      R    r        R    r    

F1 :  RR   Rr    Rr    rr

- the phenotype ratio will be  (3 pink : 1 white)

- the genotype ratio will be  [1 (RR) : 2 (Rr) : 1 (rr)]..


hichkok12 [17]3 years ago
4 0

RR Rr rr

1:2:1


Hope this helps

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2 years ago
In the reaction below how would adding more of product C affect the equilibrium of the system? A+B arrows both ways C+D
Shalnov [3]

Answer:

1. The reaction will proceed backward, shifting the equilibrium position to the left.

2. The reaction will proceed forward, shifting the equilibrium position to the right.

3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)

Explanation:

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3 years ago
What is the empirical formula of propene CH3 CH2 CH2​
kiruha [24]

Answer:

<u>CH</u>

Explanation:

Molecular formula of propene : <u>C₃H₆</u>

Take the HCF of carbon and hydrogen atoms :

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  • 6 = 2 x 3

Then, we can write the formula as :

  • 3CH
  • This means there are 3 moles present

Empirical Formula :

  • Molecular Formula / No. of moles
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<u></u>

The empirical formula of propene is <u>CH</u>

6 0
1 year ago
What is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa
Nezavi [6.7K]

60.7 ml is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa.

Explanation:

Data given:

V1 = 75 ml

T1 = 30 Degrees or 273.15 + 30 = 303.15 K

P1 = 91 KPa

V2  =?

P2 = 1 atm or 101.3 KPa

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At STP the pressure is 1 atm and the temperature is 273.15 K

applying Gas Law:

\frac{P1VI}{T1}= \frac{P2V2}{T2}

putting the values in the equation of Gas Law:

V2 = \frac{P1V1T2}{P2T1}

V2 = \frac{91 X 75 X 273.15}{303.15 X 101.3}

V2 = 60.7 ml

at STP the volume of carbon dioxide gas is 60.7 ml.

4 0
3 years ago
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