Each time it is being subtracted by 6.5
I would think that all but one point would be on the line. One way to approach this problem is to find the equation of the line based upon any two points chosen at random, and then determine whether or not the other points satisfy this equation. Next time, would you please enclose the coordinates of each point inside parentheses: (2.5,14), (2.25,12), and so on, to avoid confusion.
14-12
slope of line thru 1st 2 points is m = ---------------- = 2/0.25 = 8
2.50-2.25
What is the eqn of the line: y = mx + b becomes
14 = (8)(2.5) + b; find b:
14-20 = b = -6. Then, y = 8x - 6.
Now determine whether (12,1.25) lies on this line.
Is 1.25 = 8(12) - 6? Is 1.25 = 90? No. So, unless I've made arithmetic mistakes, (1.25, 5) does not lie on the line thru (2.5,14) and (2.25,12).
Why not work this problem out yourself using my approach as a guide?
Answer:
(2/3)^2
Step-by-step explanation:
Answer:
true
Step-by-step explanation:
for a right triangle no
Answer:
The answer to your question is (-1, 2)
Step-by-step explanation:
Data
y = -4x - 2 Equation l
y = 2x + 4 Equation ll
Process
-Graph equation l (green line)
Plot the point (0, -2)
Starting from this point plot the point (1, -4), this point comes from the slope.
-Graph the equation ll (blue line)
Plot the point (0, 4)
Plot the point (1, 2) starting from the previous point.
-The solution is the point where the lines cross. This point is (-1, 2)