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PLEASE HELP ASAP Factor 3x+6y-9z

Effectus [21]

I’m not sure what the answer is so better I don’t say I don’t want you to get it wrong

3 0

3 years ago

If y varies directly as x2 and y=6 when x=6, find the constant of variation.

Feliz [49]

Answer:

The constant of variation is 1/6

Step-by-step explanation:

If we have direct variation the formula is

y = kx^2

We know that y = and x=6

6 = k*6^2

6 = k*36

Divide each side by 36

6/36 = k36/36

1/6 =k

The constant of variation is 1/6

7 0

4 years ago

Read 2 more answers

Christina earns $250 a week. To budget money, she pays $135 in bills each week. How much money does Christina have left at the e

Rama09 [41]

Answer:

460 USD

Step-by-step explanation:

monthly earnings = 250 x 4 = 1000

monthly bills = 135 x 4 = 540

end of month = 1000 - 540 = 460 USD

7 0

3 years ago

2х5y-3z-=14 x-2y+=-12 -x+ Зу-2z =13

lukranit [14]

Answer:

x = -34/3, y = 1/3, and z = -35/3

Step-by-step explanation:

2х+5y-3z-=14 let's call this equation 1.

x-2y=-12 let's call this equation 2.

-x+Зу-2z =13 let's call this equation 3.

USING EQUATION 1 AND EQUATION 3.

2х+5y-3z-=14 (EQUATION 1)

-x+Зу-2z =13 (EQUATION 3)

LET'S GET RID OF z, BY MAKING THE COEFFICIENT OF z IN THE TWO EQUATION THE SAME. WE WILL MULTIPLY EQUATION 1 BY 2 AND EQUATION 3 BY 3.

2х+5y-3z-=14 (EQUATION 1) * 2

-x+Зу-2z =13 (EQUATION 3) * 3

4х+10y-6z-=28 let's call this equation 4.

-3x+9у-6z =39 let's call this equation 5.

TO GET RID OF z, WE WILL HAVE TO SUBTRACT EQUATION 5 FROM EQUATION 4 PLEASE TAKE NOTE OF THE SIGNS (-) (+).

4х+10y-6z-=28 (EQUATION 4)

- (-3x+9у-6z =39) (EQUATION 5)

(4x - 3x) + ((+10y) - (+9y)) + ((-6z) - (-6z)) = (28 - 39)

x + y + 0 = -11

x + y = -11 let's call this equation 6.

USING EQUATION 2 AND EQUATION 6, LET'S FIND x AND y.

x-2y=-12 (EQUATION 2)

x + y = -11 (EQUATION 6)

x has the same coefficient in both equations, which is 1. Let's get rid of x so we can find the value of y.

We will subtract equation 6 from equation 2. Take note of the signs.

x-2y=-12 (EQUATION 2)

- (x + y = -11) (EQUATION 6)

(x - x) + ((-2y) - (+y)) = ((-12) - (-11))

0 + -3y = -1

-3y = -1

Divide both sides by -3.

-3y/-3 = -1/-3

y = 1/3

LET'S SUBSTITUTE THE VALUE OF y INTO EQUATION 2 TO GET THE VALUE OF x.

x-2y=-12 (EQUATION 2)

x-2(1/3)=-12

x -2/3 = -12

Add 2/3 to both sides.

x -2/3 + (2/3) = -12 + (2/3)

x + 0 = -34/3

x = -34/3

LET'S SUBSTITUTE THE VALUES OF x and y INTO EQUATION 1 TO GET THE VALUE OF z.

2х+5y-3z-=14 (EQUATION 1)

2(-34/3)+5(1/3)-3z-=14

-68/3 + 5/3 - 3z = 14

-21 - 3z = 14

Add 21 to both sides.

-21 + (21) - 3z = 14 + (21)

0 - 3z = 35

-3z = 35

Divide both sides by -3.

-3z/-3 = 35/-3

z = -35/3 or

Therefore, x = -34/3, y = 1/3, and z = -35/3

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6 0

3 years ago

find the equation of the straight line passing through the point (0,1) which is perpendicular to the line y=-2x+2

Inessa [10]

Answer:

y = 1/2x + 1

Step-by-step explanation:

In order to evaluate a slope that is perpendicular to the given equation, you need to find the opposite reciprocal of the original slope. This means you take the original slope, flip the numerator and the denominator, and change the sign in front.

-2 ⇒ 1/2

Next, we need to substitute the information given into the point-slope formula.

The point-slope formula is:

y - y₁ = m(x - x₁)

y - 1 = 1/2(x - 0)

y - 1 = 1/2x

y = 1/2x + 1

Therefore, the line perpendicular to y = -2x + 2 is y = 1/2x + 1.

8 0

3 years ago