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3 years ago

Name two different numbers that round to 3.8 when rounded to the nearest tenth.

Mathematics

2 answers:

AveGali [126]3 years ago

6 0

Answer:

3.78 and 3.79

You aren't limited to just one decimal place.

maxonik [38]3 years ago

3 0

Two numbers that round to 3.8 when rounding to the nearest tenth can be 3.78 and 3.79

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Help me please answer

neonofarm [45]

Answer:

Volume of cone = 90 ft³

Step-by-step explanation:

diameter of cone = 6ft

radius of cone = 3ft

height = 10ft

Volume of cone = $\frac{\pi r^2h}{3}$

V = (3 × 3 × 3 × 10)/3

V = 270/3

V = 90 ft³

3 0

2 years ago

Is 90 1/10th of 900?

mestny [16]

Yes, 90 is 1/10 of 900

Because

90 = 1/10 x 900
90 = 90

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3 years ago

Find the area of the regular polygon

gregori [183]

Answer:To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothem. Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothem = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.

Step-by-step explanation:

hope this helps

plez mark as brainlyest

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3 years ago

Create an equation that has a solution of 6.

PolarNik [594]

2x=12 is an equation with the solution of 6

5 0

3 years ago

Determine the most precise name for ABCD (parallelogram, rhombus, rectangle, or square). Explain how you determined your answer.

Sonja [21]

<h3>Answer: Rhombus</h3>

======================================================

Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\$

Segment AB is exactly $\sqrt{17}$ units long, which is approximately 4.1231 units.

If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2,y_2) = (7,6)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{6 - 5}{7 - 3}\\\\m = \frac{1}{4}\\\\$

Segment AB has a slope of 1/4.

Do the same for BC

$B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2) = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\$

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.

4 0

2 years ago

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