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Aleks [24]
3 years ago
6

11) - V12 + 3V3 Simplify

Mathematics
1 answer:
allsm [11]3 years ago
6 0

Answer:

\large\boxed{-\sqrt{12}+3\sqrt3=\sqrt3}

Step-by-step explanation:

-\sqrt{12}+3\sqrt3=-\sqrt{4\cdot3}+3\sqrt3\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=-\sqrt4\cdot\sqrt3+3\sqrt3=-2\sqrt3+3\sqrt3=(-2+3)\sqrt3=1\sqrt3=\sqrt3

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<h3>Quadratic equation</h3>

From the question, we are to determine the roots of the given equation

The given equation is

x² -5x +2 = 0

Using the formula method,

x =\frac{-b \pm \sqrt{b^{2}-4ac } }{2a}

In the given equation,

a = 1, b = -5, c = 2

Putting the values into the formula,

x =\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(2) } }{2(1)}

x =\frac{5 \pm \sqrt{25-8} }{2}

x =\frac{5 \pm \sqrt{17} }{2}

x =\frac{5 + \sqrt{17} }{2} OR x =\frac{5 - \sqrt{17} }{2}

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x = 4.56 OR x = 0.44

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Learn more on Quadratic equation here: brainly.com/question/8649555

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