An outlier is an observation that lies outside the overall pattern of a distribution. Usually, the presence of an outlier indicates some sort of problem. This can be a case which does not fit the model under study, or an error in measurement.hope this helps<span>
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Answer:
KF = 35
Step-by-step explanation:
Since it's a line with K in the middle, we know that the distance SF is the same as SK + KF.
(Start at S, first go to K, then continue to F. You've traveled the same distance as from S to F.)
SF = SK + KF
Let's put in the values we got.
5x + 2 = 27 + (3x -1)
Opening the parenthesis.
5x + 2 = 27 + 3x - 1
5x + 2 = 26 + 3x
Now let's subtract 3x from both sides.
2x + 2 = 26
Now, subtract 2 from both sides.
2x = 24
If we divide by 2...
x = 12
We know that...
KF = 3x -1
Since x is 12, let's put that in.
KF = 3 * 12 - 1 = 36 - 1 = 35
Answer: KF is 35 !
We have:
As 5 has no perfect square factors, we have completely simplified this expression.
Okay so:
To multiply two trinomials, we will have to multiply each term of the second trinomial by the first term of the first trinomial and then repeat the multiplication by multiplying each term of the second trinomial by the second term of the first trinomial and finally, multiply each term of the second trinomial by the third term of the first trinomial. This can be done by either the horizontal method or the vertical method of multiplication. Now, group the like terms together and add them.
Given below are some of the examples in solving trinomials multiplication.
Trinomials can be applied various operations just as other polynomials, like - addition, subtraction, multiplication and division. Especially, we are going to study about multiplication of trinomials. The distributive method can be used to multiply two trinomials. In this case, multiplicand and the multiplier both are trinomials. Multiplication of the trinomials can be done by either the horizontal method or the vertical method of multiplication. Let us go ahead and learn how to multiply two or more trinomials together.
Alright Hope this helps you
<BAX = <ADY
AB || CD Property of a square.
<BAX = Theta Naming an angle (doesn't need proof)
<BAX = <AZD Property of parallel lines
<ZDY = 90 - Theta Right angle triangle
<YDA = theta The two angles at D are complementary.
Which was what you were intended to prove.
Triangle DAY and ABX are Congruent.
You know this because you have two angles and a side that are equal. If two angles in a triangle are equal then the third angle is equal. You have AAS but you could easily make it into ASA. The key step is the one above.
Nice problem. Thanks for posting.
