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inn [45]
2 years ago
15

Which is/are part of the macroscopic domain of solutions and which is/are part of the microscopic domain: boiling point elevatio

n, Henry’s law, hydrogen bond, ion-dipole attraction, molarity, nonelectrolyte, osmosis, solvated ion?
Chemistry
1 answer:
Juliette [100K]2 years ago
7 0

Answer:

Macroscopic domain: Boiling point elevation, Henry's law, molarity, osmosis.

Microscopic domain: Hydrogen bond, ion-dipole attraction, nonelectrolyte, solvated ion.

Explanation:

A solution is composed of a solute (in high quantity) and one or more solute, which are dissolved in it. The properties of the solution can be characterized and measured in the macroscopic domain, or the microscopic domain when it's observed in the interactions with the molecules.

Boiling point elevation: It happens because the nonvolatile solvents interact with the solute, and so it will be difficult to boil it. The boiling point is a property of all the substance, and so, it can be noticed in the macroscopic domain.

Henry's law: States that the solubilization of a gas in a liquid depends on the partial pressure of the gas and by a proportional constant. Thus, the solubility of a gas is how much moles are dissolved in the volume of the solution, and so it's part of the macroscopic domain.

Hydrogen bond: It's an intermolecular interaction that happens in polar molecules that have bonds between hydrogen and a high electronegative element (N, O, or F). So, it's part of the microscopic domain.

Ion-dipole attraction: It's also an interaction that happens between an ion and a polar compound, so it's part of the microscopic domain.

Molarity: It represents how much moles of the solute is dissolved in the solution, so it's part of the macroscopic domain.

Nonelectrolyte: An electrolyte compound is the one which dissociates or ionizes, in the solvent, and because of that the solution can conduct electricity. A nonelectrolyte doesn't have this property. Because it depends on how the ions and molecules behave in solution, it's part of the microscopic domain.

Osmosis: Is the property of the solvent to go through a membrane from a side with fewer solutes (less concentrated) to another with more solute (high concentrated). So, it depends on the total amount of the solute, and so it's part of the macroscopic domain.

Solvated ion: A solvated ion is an ion that is surrounded by another ion, or by molecules, such water. So, it's part of the microscopic domain.

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Name the following ionic compounds, keeping in mind that a transition metal cation must include its charge. ____________________
Lilit [14]

Answer :

(a) The name for TiO_2 is titanium(IV) oxide.

(b) The name for BaCl_2 is barium chloride.

(c) The name for CuCl_3 is copper(III) chloride.

(d) The name for KI is potassium iodide.

(e) The name for SrCl_2 is strontium chloride.

(f) The name for CuBr_2 is copper(II) bromide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) TiO_2

TiO_2 is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for TiO_2 is titanium(IV) oxide.

(b) BaCl_2

BaCl_2 is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for BaCl_2 is barium chloride.

(c) CuCl_3

CuCl_3 is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for CuCl_3 is copper(III) chloride.

(d) KI

KI is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for KI is potassium iodide.

(e) SrCl_2

SrCl_2 is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for SrCl_2 is strontium chloride.

(f) CuBr_2

CuBr_2 is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for CuBr_2 is copper(II) bromide.

3 0
3 years ago
What is the energy released or absorbed as heat when one mole of a compound is produced by combination of its elements? select o
suter [353]
B and D is out. It cant be A because heat of combustion is substance not compound. So the answer is D.
7 0
3 years ago
How many significant figures are in the following number? 0.000485
aliina [53]

Answer:

4 or 3

Explanation:

8 0
3 years ago
Read 2 more answers
You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

3 0
3 years ago
At the beginning of an experiment, a scientist has 176 grams of radioactive goo. After 165 minutes, her sample has decayed to 5.
Paul [167]
The half-life equation is written as:

An = Aoe^-kt

We use this equation for the solution. We do as follows:

5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes? 
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE


Find a formula for G(t) , the amount of goo remaining at time t.G(t)=? 

G(t) = 176e^-0.02t

How many grams of goo will remain after 50 minutes? 

G(t) = 176e^-0.02(50) = 64.75 g
6 0
3 years ago
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