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GREYUIT [131]
3 years ago
10

Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound?

Chemistry
1 answer:
iVinArrow [24]3 years ago
4 0

The  number of atoms  of K that are in 235 g  of the compound  is

2.57 x10^24 atoms


 calculation

Step 1:  find the moles of K2S

= moles = mass/molar mass

=  235 g/110 g/mol= 2.136  moles

Step 2: multiply  2.136 moles  by no. of K atoms in K2S

= 2.136  x2 = 4.272 moles


Step 3: use the Avogadro's  law to determine number of K atoms

that is according to Avogadro's law  1 mole = 6.02 x 10^23  atoms

                                                            4.272 moles= ? atoms

by cross multiplication

= (4.272  moles x 6.02 x10^23 atoms)  / 1 mole = 2.57 x10^24 atoms

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The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co
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Answer:

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

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m_{sw} = \rho_{sw}\cdot V_{sw}

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If V_{sw} = 1.5\times 10^{21}\,L and \rho_{sw} = 1030\,\frac{g}{L}, then:

m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)

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m_{NaCl} = r\cdot m_{sw}

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